(t^2+1)^100
USE CHAIN RULE
Outside first (using power rule)
100*(t^2+1)^99 * derivative of the inside
100(t^2+1)^99 * d(t^2+1)
100(t^2+1)^99 * 2t
200t(t^2+1)^99
Answer: The answer would be f^-1 (x) = x/2 - 3/2
Answer: Jenny
Step-by-step explanation:
By subtitue Y = 0
0=(x-3)^2
And you get 3
A.
-1:
(-1,1)
0:
(0, 2)
1:
(1, 4)
2:
(2, 8)
3:
(3,16)b.
To graph the equation, simply go through the points (-2, 0.5), (-1, 1), (0,2), (1,4), (2,8), and (3,16). Make sure you never go below 0 on the x-axis, because there's an asymptote there.
Hope this helps!