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aleksley [76]
2 years ago
10

What is the repeated-measures t statistic for a two-tailed test using the following scores

SAT
1 answer:
amid [387]2 years ago
5 0

Based on the values in the table, the repeated measures t statistic would be b. -0.577.

<h3>What is the repeated-measures t-statistic?</h3>

The test statistic can be found as:

= (Mean difference - μd) / (Standard deviation / sample square root)

These figures can be found in a spreadsheet to be:

μd = 0

Mean difference = -1

Standard deviation = 3.4641

The test statistic is therefore:

= (-1 - 0) / (3.4641 / √4)

= - 0.577350269

= - 0.577

Find out more on test statistics at brainly.com/question/15110538

#SPJ1

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Ten year old madison was riding her brand new scooter
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kipiarov [429]

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Read 2 more answers
For the galvanic (voltaic) cell fe(s) + mn²⁺(aq) ⟶ fe²⁺(aq) + mn(s) (e° = 0.77 v at 25°c), what is [fe²⁺] if [mn²⁺] = 0.050 m an
Nuetrik [128]

The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.

<h3>What is the Nernst Equation?</h3>

The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:

\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}

where;

  • n = Number of electrons = 2
  • \mathbf{E_o} = Initial voltage = 0.77 V
  • \mathbf{E_{cell}} = Cell voltage = 0.78 V
  • \mathbf{[Mn^{2+}]} = Manganese concentration = 0.050 M

Replacing the values into the above equation, we have:

\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{Fe^{2+} = (0.4594\times 0.050 )\ M}

\mathbf{Fe^{2+} =0.02297 \ M }

Learn more about using the Nernst equation here:

brainly.com/question/24258023

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2 years ago
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