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AysviL [449]
1 year ago
6

Graph f(x)=2x+1 and g(x)=−x+7 on the same coordinate plane.

Mathematics
1 answer:
Tamiku [17]1 year ago
8 0

Answer:

x = 2

Step-by-step explanation:

To solve the equation, you need to set both functions equal to each other and simplify to find the value of "x".

f(x) = 2x + 1

g(x) = -x + 7

f(x) = g(x)                                              <----- Given equation

2x + 1 = -x + 7                                      <----- Insert functions

3x + 1 = 7                                             <----- Add "x" to both sides

3x = 6                                                  <----- Subtract 1 from both sides

x = 2                                                    <----- Divide both sides by 3

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Answer:

3.1

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8 0
3 years ago
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ioda

Answer:

<em>First Option; 40,</em>

<em>Second Option; x = 3,</em>

<em>Third Option; x = - 5,</em>

<em>Fourth Option; x = 0</em>

Step-by-step explanation:

Given the expression x^2 + 3 * ( x + 4 ), where x = 4;

x^2 + 3 * ( x + 4 ) ⇒ Substitute the value of 4 in replacement of x,

( 4 )^2 + 3 * ( 4 + 4 ) ⇒ Add the terms in ( ), taking 4^2 at the same time,

16 + 3 * ( 8 ) ⇒ By PEMDAS, multiply 3 by 8 first,

16 + 24 ⇒ And now add the remaining terms,

<em>Solution; 40</em>

This next equation is given to be 5 * ( 2x - 1 ) = 25, where we must solve for x;

5 * ( 2x - 1 ) = 25 ⇒ Distribute the 5 to the terms in ( ),

10x - 5 = 25 ⇒ Add 5 on either side of the equation,

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Here we must solve for the value of x provided the equation 6x + 4 - x = 2x - 11;

6x + 4 - x = 2x - 11 ⇒ Add 11 on either side,

6x + 15 - x = 2x ⇒ Add x on either side of equation,

6x + 15 = 3x ⇒ Subtract 6x on either side,

15 = - 3x ⇒ Divide 3 on either side,

<em>Solution; x = - 5 </em>

Now we are given the equation 4 - ( 3x + 4 ) = - 9x, solving for the value of x;

4 - ( 3x + 4 ) = - 9x ⇒ Distribute the - 1 to all terms in ( ),

4 - 3x - 4 = - 9x ⇒ Add 3x on either side of equation,

4 - 4 = - 6x ⇒ Subtract 4 from 4,

0 = - 6x ⇒ Divide - 6 on either side,

<em>Solution; x = 0</em>

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