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adoni [48]
2 years ago
12

Find the area of a triangle with base of 6m and height of 15m

Mathematics
2 answers:
dusya [7]2 years ago
7 0

Answer:

45 meters

Step-by-step explanation:

Area=\frac{1}{2}bh\\ A=\frac{1}{2}(6)(15)\\ A=3(15)\\A=45

My name is Ann [436]2 years ago
3 0

⊱________________________________________________________⊰

Answer:

A=45 m²

Step-by-step explanation:

The formula for the area of a triangle is, \bigstar\underline{\boxed{\sf{A=\frac{bh}{2}}}}.

where :

\triangleright\sf{A=Area,b=base,h=height}\triangleleft

<em>Substitute the values,</em>

<em />\large\begin{gathered}\sf{A=\frac{6*15}{2} \\ \sf{A=\frac{90}{2}\\\bigstar\underline{\boxed{\sf{A=45 \ m^2}}}} \end{gathered}

Done !! Hope this made sense to you :)

\small\boldsymbol{Calligraphy}

⊱______________________________________________________⊰

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Simplify: 9x - (-19 + 11x)<br><br> i’m really bad at math so please help.
matrenka [14]

Answer:

-2x+19

Step-by-step explanation:

9x-(-19+11x)=9x+19-11x=-2x+19

3 0
3 years ago
Read 2 more answers
Algebra 2 help. Solving equations containing two radicals
Marysya12 [62]

These are 3 questions and 3 answers.

Question 1.

Answer: bot equations have the same potential solutions, but equation A may have extraneous solutions

Explanation:

1) Equation A

\sqrt{x^2+3x-6}=\sqrt{x+2}\\ \\  x^2+3x-6=x+2\\ \\  x^2+2x-8=0\\ \\  (x+4)(x-2)=0\\ \\  x=-4 ; x =2

Replace x = -4 in the right side of the equation:

\sqrt{x+2} =\sqrt{-4+2} =\sqrt{-2}

Which is not defined, so this is a extraneous solution.

2) Equation B.

Since it is a cube root, it is defined for any (negative, zero, and positive) values of x.

Question 2.

Answer: cubing both sides once.

Explanation:

\sqrt[3]{5x-2} -\sqrt[3]{4x} =0\\ \\  \sqrt[3]{5x-2} =\sqrt[3]{4x}\\  \\  (\sqrt[3]{5x-2} )^3=(\sqrt[3]{4x})^3\\  \\  5x-2=4x\\ \\  5x-4x=2\\ \\  x=2

3) Question 3.

Answer: c - 2 = 25 + c + 10√c

Explanation:

\sqrt{c-2} -\sqrt{c} =5\\ \\ \\  \sqrt{c-2} =\sqrt{c} +5\\ \\  (\sqrt{c-2})^{2}  =(\sqrt{c}+5)^2\\  \\  c-2=c+10\sqrt{c} +25\\ \\  c-2=25+c+10\sqrt{c}

4 0
3 years ago
What is the following qoutient? 3√8/4√6​
kogti [31]

Answer:

3                     sqrt(3)

-----------    or  -----------

2 sqrt(3)            2

Step-by-step explanation:

3 sqrt(8)

-----------------

4 sqrt(6)

3 sqrt(4*2)

-----------------

4 sqrt(3*2)

We know that sqrt(ab) = sqrt(a) sqrt(b)

3 sqrt(4) sqrt(2)

------------------------

4 sqrt(3) sqrt(2)

Canceling the sqrt(2) and sqrt(4) is 2

3*2

----------

4 sqrt(3)

3

-----------

2 sqrt(3)

We can simplify the answer be multiplying by sqrt(3)/sqrt(3)

3                 sqrt(3)

----------- * ----------

2 sqrt(3)     sqrt(3)

3 sqrt(3)

-----------

2 *3

sqrt(3)

-----------

2

3 0
3 years ago
The table below shows the ticket rates for whale watching trips offered by Beluga Fun Tours: Age Ticket Price Under 3 years free
Rudik [331]
We have the following data:
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 3 to 12 years = $ 34
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 103 people
 There were 64 children aged 12 and under, of which some children were under 3 years
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 We have then that the equation is
 34 * (64-x) + 45 (103-64) = C
 answer
 C = 34 * (64-x) + 45 (103-64)
5 0
4 years ago
If the area of the trapezoid below is 98 square units,what is the value of x?<br>Plz help!
aleksandrvk [35]
Area of Trapezoid is = 1/2 x height x (base1 + base2)

Here, Area = 98, base1 = 8, base2 = 20 and height = unknown (x)

So, 1/2 x height x (8+20) = 98
==> 1/2 x height x 28 = 98
==> height x 14 = 98 
==> height = 98/14 
==> height = 7 units

So, the final answer is --> the value of x = 7 units



4 0
3 years ago
Read 2 more answers
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