Question

A(4,3) B(1/2, 1/5) C( 3/4, 7/4). Which point lies on the circumstance of the unit circle?

Answer 1

None of the three points (A, B, C) lies on the circumference of the unit circle.

What point is in the circumference of an unit circle?

Unit circles are circles centered at the origin and with a radius of 1. A point is on the circumference if and only if the distance of the point respect to the origin is equal to 1. The distance of each point is determine by Pythagorean theorem:

Point A

$d = \sqrt{4^{2}+3^{2}}$

d = 5

Point B

$d = \sqrt{\left(\frac{1}{2} \right)^{2}+\left(\frac{1}{5}\right)^{2} }$

d = √29 /10

d ≈ 0.539

Point C

$d = \sqrt{\left(\frac{3}{4} \right)^{2}+\left(\frac{7}{4} \right)^{2}}$

d = √58 /4

d ≈ 1.904

None of the three points (A, B, C) lies on the circumference of the unit circle.

Remark

The statement presents a typing mistake, correct form is shown below:

A(x, y) = (4, 3), B(x, y) = (1/2, 1/5), C(x, y) = (3/4, 7/4). Which point lies on the circumference of the unit circle?

To learn more on circles: brainly.com/question/11987349

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