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puteri [66]
2 years ago
9

Given the IPv4 address in CIDR notation 215.200.110.50/25, identify the subnet ID that this address belongs to.

Computers and Technology
1 answer:
stich3 [128]2 years ago
7 0
215.200.110.00, 215.100.110.64, 215.200.110.128,215.100.110.192
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Charles Lyell believed that:
yuradex [85]
D: slow processes of erosion and deposition shaped the earth
8 0
3 years ago
Put the following steps of the problem solving process in correct order.
Goryan [66]
It is already in a correct order
3 0
3 years ago
Assume that the classes listed in the Java Quick Reference have been imported where appropriate.
Neko [114]

The following java code will be written for the prescribed

<u>Explanation:</u>

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

      for(int i=0;i<arr.length;i++){

          if(name.equals(arr[i]))

              return true;

      }

      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

              this.possibleNames.remove(index);

              names = new String[this.possibleNames.size()];

              names = this.possibleNames.toArray(names);

          }

      }

  }

  public boolean isValidName(String str){

      if(str.length()==0) return false;

      for(int i=0;i<str.length();i++){

          if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

              return false;

      }

      return true;

  }

  public static void main(String[] args) {

      UserName person1 = new UserName("john","smith");

      System.out.println(person1.possibleNames);

      String[] used = {"harta","hartm","harty"};

      UserName person2 = new UserName("mary","hart");

      System.out.println("possibleNames before removing: "+person2.possibleNames);

      person2.setAvailableUserNames(used);

      System.out.println("possibleNames after removing: "+person2.possibleNames);

  }

}

7 0
4 years ago
Match the following terms and definitions.
vovikov84 [41]

Answer:

1. Spaghetti code.

2. Business process management.

3. Procure-to-pay

4. Order-to-cash

5. User tier

6. Firewall

7. Database tier

8.Application tier

9. Three-tier architecture

Explanation:

1.Programming code used to connect stand-alone systems is spaghetti code.

2. Transforming business processes to improve efficiency business process management.

3. Corresponds to the purchasing cycle is called procure to pay.

4. Corresponds to the sales cycle is order-to-cash

5. Consists of front-end client computers and the user interface is user tier.

6. Software programs on a router that monitor network traffic is firewall

7. Comprised of a centralized relational database and an RDBMS is database tier.

8. Consists of servers and application software is application tier.

9. When an enterprise system uses layers of IT components: enterprise database, application, and client computers is three tier architecture.

4 0
4 years ago
A taxi cab costs $1.25 for the first mile and $0.25 for each additional mile. Write an
Mumz [18]

Answer:

0.25x+1.25=8

Explanation:

Hope this helps

3 0
3 years ago
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