Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Answer:
x = 9
Step-by-step explanation:
The two angles are alternate exterior and has same measurement
15(x+1) = 150 divide both sides by 15
x + 1 = 10 subtract 1 from both sides
x = 9
#2
Change mixed numbers to improper fractions. Then change division to multiplication by the reciprocal.
1 1/2 divided by 3/5=
(3/2) * (5/3) = 5/2 = 2 1/2
#3
(5/9) divided by (5/3)
(5/9) * (3/5) =3/9 = 1/3
Answer:
Step-by-step explanation:
