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mars1129 [50]
2 years ago
9

Let sets A and B be defined as follows.

Mathematics
1 answer:
VashaNatasha [74]2 years ago
5 0
<h3>Given</h3>

  • Set A: A = {-26, -25, -24, -23, - 22, - 21}
  • Set B: B ∈ {x: x is even, x ≥ 6 and x ≤ 20}

<h3>(a) </h3>

<em />

<em>Cardinality means the number of elements in the set.</em>

Cardinality of the set A:

n(A) = 6, since we can count 6 elements.

Set B has even numbers between 6 and 20, both included:

  • B = {6, 8, 10, 12, 14, 16, 18, 20}

Then its cardinality is:

  • n(B) = 8

<h3>(b) </h3>

To solve this we need to compare the elements of sets A or B with numbers given:

  • -22 ∈ A, True       ⇒  -22 is listed as element of A
  • 6 ∈ B, True          ⇒  6 is listed as element of B
  • - 21 ∉ A, False     ⇒  - 21 is listed as element of A
  • 2 ∈ B, False         ⇒  2 is not listed as element of B
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Determine the angle at the centre of a circle with radius 12.0 cm for an arc length of of 21.0 cm.
nata0808 [166]

Answer:

\theta=\dfrac{7}{4}\ \text{radian}

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A polyhedron with two parallel congruent faces called bases connected by parallelogram faces is called a...
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3 years ago
PlZ HELP WILL MARK YOU AS THE BRAINLIEST!
defon

Answer:

1. distance = sqrt( (7-7)^2+(2- -8)^2) = 10

2.  check out desk (0,0 ) => distance = sqrt( (0- -9)^2+(0-0)^2) = 9

3. last corner ( -3, 4)

4. area = sqrt( (-10- -10)^2+(10-4)^2) x sqrt( (-3- -10)^2+(10-10)^2) = 6x7 =42

5. check desk (0,0), south direction = negative y axis => P_beginning (0,-20), P_end (0,-(20+25)) = (0,-45)

6. A(-2,-1) and B(4,-1) lie in y =-1. AB = sqrt( (-2- 4)^2+(-1- -1)^2) =6

=> area = 3.6x6 =21.6

=> peri = 2x(3.6+6) = 19.2

7. A(-5,4) and B(2,4), AB =  sqrt( (-5- 2)^2+(4- -4)^2) = 7 => AB is base

=> p = peri = 7+ 8.3x2 = 23.6

=> area = sqrt[px(p-7)x(p-8.3)x(p-8.3)]

             =sqrt[23.6x(23.6-7)x(23.6-8.3)x(23.6-8.3)] = 302.8

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4 years ago
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