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yanalaym [24]
4 years ago
14

HURRY plssss!!! find x

Mathematics
1 answer:
vitfil [10]4 years ago
5 0

Answer: x=115\°

Step-by-step explanation:

As you can observe in the figure, the angle "x" is formed  by two intersecting chords in the circle.

It is important to remember that, by definition:

Angle\ formed\ by\ two\ intersecting\ Chords=\frac{1}{2}(Sum\ of\ Intercepted\ Arcs)

In this case you can identify that the Intercepted Arcs are:

AD=140\°\\BC=90\°

Then:

x=\frac{1}{2}(AD+BC))

Therefore, substituting values into the formula and evaluating, you get that the measure of the angle "x" is:

x=\frac{1}{2}(140\°+90\°)\\\\x=\frac{1}{2}(230\°)\\\\x=115\°

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Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he
alexgriva [62]

Answer:

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

g(t) = 0

And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

9ty + e^{t}y' = \frac{y}{t^{2} + 81 }

e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t  - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) } ]y = 0

By comparing with y′+p(t)y=g(t), we get

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

g(t) = 0

And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous.

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3 years ago
NEED ALL 4! With the solution and step by step on what to do !! worth 35 points
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Answer:

I got you, give me a few minutes

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Step-by-step explanation:

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Lee works for a company that ships packages and must measure the size of each box that needs to be shipped. Lee measures a box a
expeople1 [14]

Answer: 1852.5 cubic inches


Step-by-step explanation:

The Volume of cuboidal box is given by:-

Volume=length\times width\times\ height

Given: The length of box =9\frac{1}{2}\ inches=\frac{19}{2}\ inches

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3 years ago
O is the centre of the circle, EF is a tangent, angle BCE=28 degrees, angle ACD=31 degrees.
Yuki888 [10]

Answer:

a. 28˚

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Step-by-step explanation

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c. because angles in triangles add up to 180˚ and opposite angles in a cyclic quadrilateral add up to 180˚, 31+76=107, 180-107=73, 73-28=45, angles in triangle so 180-(31+45)=104˚

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