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sergey [27]
2 years ago
7

Jackson Brothers decided to create a petty cash fund. They estimated that $200 would be needed in the fund. Demonstrate the corr

ect journal entry to create the account by choosing the correct action from those below.
SAT
1 answer:
Dafna11 [192]2 years ago
7 0

Based on the fact that the Jackson Brothers want to create a petty cash fund, the journal entry would be:

Date                     Account title                              Debit               Credit

XX-XX-XXXX       Petty cash                                 $200

                             Cash                                                                  $200

<h3 /><h3>How is petty cash created?</h3>

In order to create the petty cash account, a cash amount needs to be debited to it to show that it is increasing in value.

The cash account would then have to be credited by the amount that the petty cash account was debited by which in this case is $200. This shows that the cash account is decreasing.

Find out more on petty cash accounts at brainly.com/question/6893535

#SPJ1

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The accompanying graph depicts demand at point d demand is
Georgia [21]

The accompanying graph depicts demand At point A, demand is: A)The accompanying graph depicts demand.

<h3>What did the graph depicts  at point A?</h3>

It depict the demands of goods at at that point.

The accompanying graph depicts demand At point A, demand is: A)The accompanying graph depicts demand.

CHECK THE COMPLETE QUESTION:

The accompanying graph depicts demand at point d demand:

A) unit elastic.

B) inelastic.

C) elastic.

D) perfectly elastic.

Learn more about demand on:

brainly.com/question/25220385

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8 0
2 years ago
Consider the following line integral. C xy dx + x2y3 dy, c is counterclockwise around the triangle with vertices (0, 0), (1, 0),
Sedaia [141]

It looks like the integral is

\displaystyle \int_C xy \, dx + x^2y^3 \, dy

Let's close the loop by adding a line integral over the line segment joining (1, 4) to (0, 0). Then the closed loop is the triangular region

T = {(x, y) : 0 ≤ x ≤ 1 and 0 ≤ y ≤ 4x}

Since the integrand has no singularities over or on the boundary of T, we have by Green's theorem

\displaystyle \int_C xy \, dx + x^2y^3 \, dy = \iint_T \left(\frac{\partial(x^2y^3)}{\partial x} - \frac{\partial(xy)}{\partial y}\right) \, dx \, dy = \int_0^1 \int_0^{4x} (2xy^3 - x) \, dy \, dx

Compute the double integral:

\displaystyle \int_0^1 \int_0^{4x} (2xy^3 - x) \, dy \, dx = \int_0^1 \int_0^{4x} \left(128x^5 - 4x^2\right) \, dx = \frac{60}3

From this result, we subtract the line integral over the extra line segment we added. Parameterize this path by

C' : {(1 - t, 4 - 4t) : 0 ≤ t ≤ 1}

The line integral over C' is

\displaystyle \int_{C'} xy \, dx + x^2y^3 \, dy = \int_0^1 (1-t)(4-4t)(-dt) + (1-t)^2(4-4t)^3(-4\,dt)

\displaystyle \int_{C'} xy \, dx + x^2y^3 \, dy = \int_0^1 \left(256 t^5-1280 t^4+2560 t^3-2564 t^2+1288 t-260 \right) \, dt = -44

so that the line integral over C alone is 60/3 - (-44) = 64.

3 0
3 years ago
Samuel has a collection of toy cars. His favorites are the 27 red ones which make up 60%, percent of his collection. How many to
Pie

0.60 × collection = 27 cars

collection = 27 cars / 0.60 . . . . divide by the coefficient of the variable

collection = 45 cars

Samuel has 45 cars in his collection.

8 0
3 years ago
Which statement describes a benefit of using fission reactions.
Fittoniya [83]

Answer:

Hope it helps. Braonliest?

7 0
2 years ago
At 900 ∘c,kc=0. 0108 for the reaction caco3(s)←→cao(s)+co2(g) a mixture of caco3, cao, and co2 is placed in a 10. 0-l vessel at
Mrac [35]

The concentration of CaCO3 increases in all cases because Q> K.

<h3>What is equilibrium?</h3>

A chemical reaction is said to have attained equilibrium when the rate of forward reaction is equal to the rate of reverse reaction. We are told that the Kc of the reaction is 0. 0108.

In the first case:

CaCO3 - 15.0 g/100g/mol/10 L = 0.015 M

CaO - 15.0 g/56 g/mol/10 L = 0.027 M

CO2 - 4.25 g/44 g/mol / 10 L = 0.0096 M

Q = [0.027] [0.0096]/0.015

Q = 0.017

Since Q > K, the concentration of CaCO3 increases

In the second case;

CaCO3 -  2.5 g/100g/mol/10 L =0.0025 M

CaO - 25.0 g/56 g/mol/10 L = 0.045 M

CO2 - 5.66 g/44 g/mol / 10 L = 0.013 M

Q = [0.045 ] [ 0.013]/[0.0025 ]

Q = 0.23

Q > K the concentration of CaCO3 increases

In the third case;

CaCO3 - 30.5 g/100g/mol/10 L =0.031 M

CaO - 25.5 g/56 g/mol/10 L =0.046 M

CO2 - 6.48 g//44 g/mol / 10 L = 0.015 M

Q = [0.046] [ 0.015]/[0.031]

Q = 0.022

Q> K hence the concentration of CaCO3 increases

Missing parts: At 900oC, Kc = 0.0108 for the reaction: CaCO3(s) <===> CaO(s) + CO2(g) A mixture of CaCO3, CaO, and CO2 is placed in a 10.0 Liter vessel at 900oC. For the following mixtures, will the amount of CaCO3 increase, decrease, or remain the same as the system approaches equilibrium? CaCO3 CaO CO2 At Equilibrium, CaCO3 will ?? 15.0 g 15.0 g 4.25 g Answer 2.5 g 25.0 g 5.66 g Answer 30.5 g 25.5 g 6.48 g Answer

Learn more about equilibrium: brainly.com/question/17960050

4 0
2 years ago
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