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lesya [120]
2 years ago
12

Find the product -2/9(-5/3) I-Ready math

Mathematics
1 answer:
Verizon [17]2 years ago
8 0

The product of the given fractions, -2/9(-5/3), is: 10/27.

<h3>How to Find the Product of Two Fractions?</h3>

Given the fractions, -2/9(-5/3), recall that minus multiplied by minus equals plus.

So therefore, the product of the two fractions would be a positive number. Thus:

-2/9(-5/3) = (-2 × -5)/(9 × 3)

-2/9(-5/3) = 10/27

Therefore, the product is: 10/27.

Learn more about product of fractions on:

brainly.com/question/82108

#SPJ1

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A tank contain 5 gallons of water joanna uses a hose to slowly add more water to the tank five gallons of water are added to the
shutvik [7]

Answer: i'm not really sure how to answer this one but i think you're wanting an answer to something. the equation for it would be 5 + 5x meaning the 5 is already there, and x is for the minutes that are they filling it up. so if the question asks how much after 5 minutes, you simply just put the 5 in place for the x.

6 0
3 years ago
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If x=3 and y=7, evaluate the following expression: 100 − 3 ( 3 − 4x )
coldgirl [10]

Answer:

100 - 3(3 - 4x) \\  = 100 - 3(3 - 4 \times 3) \\  = 100 -27 \\  = 73

4 0
2 years ago
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An object is launched directly upward with an initial velocity of 64 feet per second from a platform 80 feet high. What will be
LekaFEV [45]

Answer:

a) 63.6 ft

b) 1.99 seconds

c) 4.98 seconds

Step-by-step explanation:

a) The object will reach maximum height when its final velocity, v, is 0 m/s.

We apply one of Newton's equations of motion to solve this:

v^2 = u^2 - 2gh

where u = initial velocity = 64 ft/s

g = acceleration due to gravity = 32.2 ft/s

h = height reached by object.

Note: the equation has a negative sign because the object is going upwards, against gravity.

Hence:

0^2 = 64^2 - 2*32.2*h\\\\=> 64.4h = 4096\\\\h = 4096 / 64.4\\\\h = 63.6 ft

The object is now 63.6 ft above the platform (143.6 ft above the ground).

b) Time taken to get to that height can be gotten by using another one of Newton's equations:

v = u - gt

=> 0 = 64 - 32.2t

32.2t = 64\\\\=> t = 64 / 32.2 \\\\t = 1.99 secs

It took the object 1.99 secs to get to that height.

c) When the object begins falling to ground level, it is at a height, h =  143.6 ft and begins moving at initial velocity, u = 0 m/s.

Applying another of Newton's equations of motion, we have that:

h = ut + \frac{1}{2}gt^2

where t is the time taken to hit the floor after it begins its descent.

Therefore,

143.6 = 0*t + \frac{1}{2}*32.2t^2\\ \\143.6 = 16.1t^2\\\\t^2 = 143.6 / 16.1\\\\t^2 = 8.92\\\\t = \sqrt{8.92} \\\\t = 2.99 secs

This is the time it will take the object to hit the floor after it begins its descent.

Therefore, the total time it will take for the object to hit the ground after it is launched will be:

T = time taken to reach maximum height + time taken to hit the floor after it begins descending

T = 1.99 + 2.99

T = 4.98 seconds

6 0
3 years ago
Evaluate the expression below when x = 6 and y = 2. 6x2y3
Simora [160]

Answer:

I think that the answer is 432.

Step-by-step explanation:

6x2y3.We have x as 6 and y as 2.So we replace them with their numbers.

We'll have 6*6*2*2*3 which will give us 432. I HOPE THIS HELPS.

4 0
1 year ago
Which is a point on the circle whose center is (0, 0) and whose radius is 5?
AleksAgata [21]
Circle equation is given in the form of (x-a)²+(y-b)² = r²

Where (a, b) is the centre and 'r' is the radius

We have a circle with centre (0, 0) and radius of 5.

Substituting these value into the equation form, we have

(x-0)²+(y-0)² = 5²
x² + y² = 25

Hence, the equation of the circle is x² + y² = 25
5 0
3 years ago
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