Answer:
2
Step-by-step explanation:
We can set up equation for this one.
Let's say the number is X.
the sum of X and 14 can be expressed as : X+14
five times the sum of X and 14 can be expressed as 5(x+14)
and 5(X+14) = 80

The number is 2
Answer:
Bolt A will fit Nut A and Nut B
Step-by-step explanation:
We have the following statements:
Nut C fits on Bolt C.
Nut B fits on Bolt B.
Nut A fits on Bolt A.
Bolt C is larger than Bolt B.
Bolt A and Bolt B are exactly the same.
Then we can say that Bolt A will fit Nut A and Nut B...
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of 660, hence
.
- The standard deviation is of 90, hence
.
- A sample of 100 is taken, hence
.
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

By the Central Limit Theorem



has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213
Answer:
Step-by-step explanation:
Answer:
you should use multiatication
Step-by-step explanation: