Answer:
32% of his bats were stuck out.
Step-by-step explanation:
emerson struck out 112 times out of the total of 350 times. therefore, this can be represented as the fraction 112/350, which can be simplified to 8/25.
7(200 + 50 + 6) = (7 x 200) + (7 x 50) + (7 x 6) = 1,400 + 350 + 42 = 1,792
The answer for the first question is 10%.
Reason: The second number (110) is larger than the first number (100) by 10 it is 10% the first number.
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The answer for the second question is 25%, also.
Reason: The first number (100) is smaller than the second number (110) by 10 and it is 9.1% of the second number.
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A complex mathematical topic, the asymptotic behavior of sequences of random variables, or the behavior of indefinitely long sequences of random variables, has significant ramifications for the statistical analysis of data from large samples.
The asymptotic behavior of the sample estimators of the eigenvalues and eigenvectors of covariance matrices is examined in this claim. This work focuses on limited sample size scenarios where the number of accessible observations is comparable in magnitude to the observation dimension rather than usual high sample-size asymptotic .
Under the presumption that both the sample size and the observation dimension go to infinity while their quotient converges to a positive value, the asymptotic behavior of the conventional sample estimates is examined using methods from random matrix theory.
Closed form asymptotic expressions of these estimators are obtained, demonstrating the inconsistency of the conventional sample estimators in these asymptotic conditions, assuming that an asymptotic eigenvalue splitting condition is satisfied.
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<span>In order to determine the value of the numbers, we can set up algebraic equations to solve. For this case, we need to set up two equations since we have two unknown numbers. We do as follows:
let x = first number and y = second number
From the problem statement, we set up equations.
Equation 1 - the numbers have a difference of 0.7
x - y = 0.7
Equation 2 - the numbers have a sum of 1
x + y = 1
Solving for x and y via substitution method,
x - y = 0.7
(1-y) - y = 0.7
1 - 2y = 0.7
-2y = 0.7 - 1 = -0.3
y = 0.15 or 3/20
x - 0.15 = 0.7
x = 0.85 or 17/20
Thus, the two numbers are 0.15 and 0.85.</span>
