A distribute the 5 is the first step
Once again, I hate proofs so much.
One easy solution is to follow the common logic which is if two lines are both straight and equidistant from each other, SO THEIR PARALLEL, but since education these days asks us to write theses stupid "proofs" here's my attempt:
First off what must we prove to show that two lines are parallel??
Well, the<span> first way is </span>if<span> the corresponding angles, the angles </span>that<span> are on the same corner at each intersection, are equal. If those angles are the same, then the </span>lines are parallel<span>. The second is </span>if<span> the alternate interior angles, the angles </span>that<span> are on opposite sides of the transversal and inside the </span>parallel lines, are<span> equal, then the </span>lines are also parallel<span>.
Well angles 1, 2, 3, 4, 5, 6, 7 and 8 are equal and also 90 degrees, thus the corresponding angles and alternate interior angles are all equal, which means that these two lines are parallel. </span>
Answer:
FOURTHEEN
Step-by-step explanation:
SICX,MENTENETNT
Answer:
Either 7 or 23 - read note
Step-by-step explanation:
Substitute m for 8.
*Note: I'm not sure if anything is in parentheses so there are two possible answers depending on whether you want it done left to right or by order of operations*
Left to Right:
3(8) - 3 ÷ 3
24 - 3 ÷ 3
21 ÷ 3
7
Order of Operations:
3(8) - 3 ÷ 3
24 - 3 ÷ 3
24 - 1
23
