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mestny [16]
2 years ago
10

In 4 weeks, Mark earns an average of $400 per

Mathematics
1 answer:
deff fn [24]2 years ago
7 0
4x = 400 —> x = 100 weeks 1-4
400 + 2y = 500
2y = 100
y = 50 weeks 5-6

Last three weeks
Week 4 100
Week 5 50
Week 6 50

He earned about $200
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The answer is 1/2. 1/5 is equal to 2/10, and 2/10 + 3/10 = 5/10. 5/10 is equal to 1/2 in simpelst form.
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4 years ago
Read 2 more answers
What is the length, in units, of segment CD?
leonid [27]

Answer:

The answet is C.

Step-by-step explanation:

First, you have to find the angle of ACB using Sine Rule, sinθ = opposite/hypotenuse :

\sin(θ )  =  \frac{oppo.}{hypo.}

let \: oppo. = 4 \\ let \: hypo. = 5

\sin(θ)  =  \frac{4}{5}

θ = {\sin( \frac{4}{5} ) }^{ - 1}

θ = 53.1 \: (1d.p)

Given that line AB is parallel to line CD so ∠C = 90°. Next, you have to find the angle of ACD :

ACD = 90 - 53.1 = 36.9

Lastly, you can find the length of CD using Cosine rule, cosθ = adjacent/hypotenuse :

\cos(θ)  =  \frac{adj.}{hypo.}

let \: θ = 36.9 \\ let \: adj. = 5 \\ let \: hypo. = CD

\cos(36.9  )  =  \frac{5}{CD}

CD \cos(36.9)  = 5

CD =  \frac{5}{ \cos(36.9) }

CD = 6.25 units\: (3s.f)

4 0
3 years ago
Find area of the shaded region.
anyanavicka [17]

Answer:

area of shaded portion = 226.09 m²

Step-by-step explanation:

area of circle = πr² = (3.14)(18.6²) = 1086.314 m²

area of 123° segment = (123/360)(1086.314) = 371.157 m²

cos 61.5° = height/18.6 = 8.875

height of triangle = 8.875 m

sin 61.5° = 1/2base/18.6 = 16.346,   base = 32.692 m

base of triangle = 32.692 m

area of triangle = 1/2bh = 1/2(8.875)(32.692) = 145.071 m²

area of shaded portion = 371.157 - 145.071 = 226.09 m²

5 0
3 years ago
Use the permutation formula to solve a problem when
rodikova [14]
B B B B B B B B B B B B B B B B B

8 0
2 years ago
Help pls ! This is trigonometric function
storchak [24]

Answer:

Amplitude: 4

Period: π

midline: y = 1

Step-by-step explanation:

r(x) = -4 sin(2x) + 1

r(x) = a sin(bx + c) + d where |a| is the amplitude and |b| for the period

a = -4         |a| = 4 :   Amplitude = <u>4</u>

b = 2          |b| = 2     period of sin(x) = 2π

                                period of sin(bx + c) = 2π/|b| = 2π/2 = <u>π</u>

range of sin(2x) ... -1 ≤ sin(2x) ≤ 1

range of -4 sin(2x) + 1: -4+1 ≤ -4 sin(2x) + 1 ≤ 4+1    

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midline: y = (-3 + 5) / 2 = 1        y = 1

                   

8 0
3 years ago
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