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zhenek [66]
1 year ago
8

Ignoring the effects of friction, what is the mechanical advantage of using the ramp as opposed to lifting the gurney straight u

p
SAT
1 answer:
kow [346]1 year ago
7 0

The mechanical advantage of using the ramp is given as  2.

<h3>How to solve for the mechanical advantage?
</h3>

The formula for Mechanical advantage is given as

hypotenuse / height

and also weight of object /force

The ratio of the right angled triangle is going to be

x : x√3 : 2x. Thus:

When this is rewritten , we would have

MA = 2x / x = 2

<h3>What is mechanical advantage?</h3>

In physics, the mechanical advantage is used to refer to the ratio of a force produced by a given machine to the force that was applied to that particular machine. This is the advantage that is gained by the fact that a mechanism is used to transmit force.

The assumption that is made would be that no friction would be in existence that may cause any forms of alterations in the system.

Hence we conclude that the MA in the system is given as 2.

Read more on mechanical advantage here:

brainly.com/question/18345299

#SPJ1

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Read 2 more answers
For the galvanic (voltaic) cell fe(s) + mn²⁺(aq) ⟶ fe²⁺(aq) + mn(s) (e° = 0.77 v at 25°c), what is [fe²⁺] if [mn²⁺] = 0.050 m an
Nuetrik [128]

The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.

<h3>What is the Nernst Equation?</h3>

The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:

\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}

where;

  • n = Number of electrons = 2
  • \mathbf{E_o} = Initial voltage = 0.77 V
  • \mathbf{E_{cell}} = Cell voltage = 0.78 V
  • \mathbf{[Mn^{2+}]} = Manganese concentration = 0.050 M

Replacing the values into the above equation, we have:

\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{Fe^{2+} = (0.4594\times 0.050 )\ M}

\mathbf{Fe^{2+} =0.02297 \ M }

Learn more about using the Nernst equation here:

brainly.com/question/24258023

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