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2 years ago

Which of the following statements holds true regarding sleep

SAT

1 answer:

Levart [38]2 years ago

4 0

The statement that holds true about sleep is; the sleeping state can be immediately reversed; option D.

<em>Note that the complete question is given as follows:</em>

<em>Which of the following holds true regarding sleep?</em>

<em>A. The conscious mind and the outside world completely draw a blank.</em>

<em>B. The sleeping state is irreversible.</em>

<em>C. The sleeping state has the conscious mind perceiving all the sensations of the outer world.</em>

<em>D. The sleeping state can be immediately reversed.</em>

<em />

<h3>What is sleep?</h3>

Sleep is a semi-conscious state of the mind and the body in which the body rests in order to recover from a strenuous activity.

The sleeping state can be easily reversed to full consciousness when the person sleeping is awoken.

In conclusion, sleeping is not a permanent but a reversible state.

Learn more about sleep at: brainly.com/question/4119396

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Students in a statistics class are conducting a survey to estimate the mean number of units students at their college are enroll

Andrew [12]

Using the t-distribution, as we have the standard deviation for the sample, it is found that the 95% confidence interval for the number of units students in their college are enrolled in is (11.7, 12.7).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm t\frac{s}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

t is the critical value.

n is the sample size.

s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed <em>95% confidence interval</em>, with 49 - 1 = <em>48 df</em>, is t = 2.0106.

Hence:

$\overline{x} - t\frac{s}{\sqrt{n}} = 12.2 - 2.0106\frac{1.6}{\sqrt{49}} = 11.7$

$\overline{x} + t\frac{s}{\sqrt{n}} = 12.2 + 2.0106\frac{1.6}{\sqrt{49}} = 12.7$

The 95% confidence interval for the number of units students in their college are enrolled in is (11.7, 12.7).

More can be learned about the t-distribution at brainly.com/question/16162795

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2 years ago

10) A competency test has scores with a mean of 255 and a standard

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Answer:

The percentage of scores higher than 72 is 99.85%

Explanation:

The empirical rule states that about 68% of observations falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)

We can use the relationship below

255-σ(61)=72

61σ=255-72

61σ=183

σ=3

The area is as shaded below

The percentage of scores higher than 72 is 99.7%+0.15%=99.85%

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