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Mekhanik [1.2K]
2 years ago
5

There are 5 blue socks in Josh’s drawer. After he removes 3 non-blue socks, the probability to pick a blue sock at random become

s . How 1/7 many non-blue socks were in Josh’s drawer originally?
Mathematics
2 answers:
stich3 [128]2 years ago
6 0

Answer: There is 5 non blue sock in Josh's drawer

Step-by-step explanation:

The denominator shows the total of nonblue and blue socks. So there are 7 non-blue and blue socks in the drawer after he removes 3 non blue socks.To find how many non-blue where in the drawer originally you need to find how many non blue are in the draw after removing the three. So you subtract 7 from 5 which gives you 2. So there are 2 non-blue socks in the drawer after removing the three. Now you need to find how many non-blue were there before he removed the three. So add the 3 non blue socks that he removed to the two that were there after which gives you five.

jek_recluse [69]2 years ago
3 0
There are 5 non blue socks
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3 years ago
The half-life of a certain radioactive element is 35 hours. If there are 904 grams of this element, how much will be left after
Cloud [144]
<h3>Answer: 226 grams</h3>

===========================================================

Explanation:

The half-life is 35 hours. This means every 35 hours, the amount of the substance is cut in half. If we started with 100 grams, then 35 hours later, we will have 50 grams. Then another 35 hours later we will then have 25 grams, and so on.

In this case, we start with 904 grams and follow this sequence:

904, 452, 226, 113, ...

Each term is cut in half. Going from term to term it takes 35 hours each. The third term 226 is the result of waiting two half-lives, which is 2*35 = 70 hours that have elapsed total.

--------------

If you want to use a formula, then it would be

y = A*\left(\frac{1}{2}\right)^{x/H}

where,

H = half-life duration (in this case, it is 35)

A = starting amount (which is 904 in this case)

x = amount of time that has elapsed (we will plug in x = 70)

y = final amount after x units of time has elapsed

note that x and H must have the same time unit. Both are in terms of hours in this case.

------------

So we will plug A = 904, x = 70, H = 35 into the formula to get...

y = A*\left(\frac{1}{2}\right)^{x/H}\\\\y = 904*\left(\frac{1}{2}\right)^{70/35}\\\\y = 904*(0.5)^{2}\\\\y = 904*(0.25)\\\\y = 226\\\\

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4 0
3 years ago
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Answer:

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Step-by-step explanation:

1/3:1

We want the ratio with whole numbers

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