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Illusion [34]
1 year ago
14

What factors significantly affect the overall bandwidth demands of a compressed video flow

SAT
1 answer:
Vanyuwa [196]1 year ago
8 0

The factors which significantly affect the overall bandwidth demand of a compressed video flow are:

  • Resolution,
  • Frame rate,
  • Activity level and
  • Investigative needs
<h3 /><h3>What is bandwidth?</h3>

This is known as a range of frequencies in a band that is used in transmitting a signal.

Video resolution determines the amount of detail in your video, or how realistic and clear the video appears. It's measured by the number of pixels.

Hence, video compression works by using a video encoding algorithm known as a codec to reduce the number of bits needed to represent a video.

Read more about<em> bandwidth</em> here:

brainly.com/question/4294318

#SPJ1

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4 0
1 year ago
For the galvanic (voltaic) cell fe(s) + mn²⁺(aq) ⟶ fe²⁺(aq) + mn(s) (e° = 0.77 v at 25°c), what is [fe²⁺] if [mn²⁺] = 0.050 m an
Nuetrik [128]

The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.

<h3>What is the Nernst Equation?</h3>

The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:

\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}

where;

  • n = Number of electrons = 2
  • \mathbf{E_o} = Initial voltage = 0.77 V
  • \mathbf{E_{cell}} = Cell voltage = 0.78 V
  • \mathbf{[Mn^{2+}]} = Manganese concentration = 0.050 M

Replacing the values into the above equation, we have:

\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{Fe^{2+} = (0.4594\times 0.050 )\ M}

\mathbf{Fe^{2+} =0.02297 \ M }

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