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Katen [24]
2 years ago
13

M(t)=120e−0.018t How much mass remains after 50 years? Round to 2 decimal places.

Mathematics
1 answer:
krok68 [10]2 years ago
8 0

The mass that would remain after 50 years is 48. 79 kilograms

<h3>How to determine the amount </h3>

It is important to note that half - life is the time it takes for amount of a substance to reduce to half of its initial value.

Given the equation

m(t)=120e−0.018t

Where

m(t) is the amount = unknown

t = time = 50 years

m(t) = 120e^0^.^0^1^8^t

Substitute the value into the equation

m(t) = 120e^0^.^0^1^8^(^5^0^)

m(t) = 120e^-^0^.^9

Find the exponential value

m(t) = 48.788399
m(t) = 48. 79 kilograms in 2 decimal places

Thus, the mass that would remain after 50 years is 48. 79 kilograms

Learn more about half-life here:

brainly.com/question/15575933

#SPJ1

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A line passes through the point (-7, 5) and has a sloe of 1/2. Which is another point that the line passes through?
Mekhanik [1.2K]

The point through which the same line is passing will be (9,13) so option (C) will be correct.

<h3>What is a line segment?</h3>

A line section that can connect two places is referred to as a segment.

A line segment is just part of a big line that is straight and going unlimited in both directions.

The line is here! It extends endlessly in both directions and has no beginning or conclusion.

The equation of any line with slope m can be given as

y = mx + c

Given,

slope m = 1/2

Point of passing  (-7, 5)

So,

5 = -7/2 + c ⇒ c = 17/2

So the equation will be,

y = x/2 + 17/2

2y = x + 17

Now checking all points (9,13) is satisfying.

2(13) = 9 + 17

26 = 26

Hence point (9,13) is passing through the line.

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7 0
2 years ago
Solve: -7(3+6x)=9(-5x+7)
Ivan

Answer:

x=28

Step-by-step explanation:

-7(3+6x)=9(-5x+7)

-21-42x=-45x+63

-21-42x-(-45x)=63

-21-42x+45x=63

-21+3x=63

3x=63-(-21)

3x=63+21

3x=84

x=84/3

x=28

7 0
3 years ago
Read 2 more answers
PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM
Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

c^{2} =a^{2} +b^{2}

c = \sqrt{a^{2} +b^{2} }

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = \sqrt{40^{2} + 9^{2} }

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = \sqrt{12^{2} + 13^{2} }

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

35^{2} = 20^{2} + b^{2}

1225 = 400 + b^{2}

b^{2} = 1225 - 400

b^{2} = 825

\sqrt{b^{2} } = \sqrt{825}

b = 5 \sqrt{33}

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

37^{2} = 20^{2} + b^{2}

1369 = 400 + b^{2}

b^{2} = 1369 - 400

b^{2} = 969

Taking square root on both sides

b = 31.12

Hope it helps.

4 0
3 years ago
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