Question

The half-life of a radioactive material is about 2 years. How much of a 5.0 kg sample of this material will remain after 4 years

Answer 1

The remaining amount after 4 years is 1.25 kg

How to determine the remaining amount?

The half life of a function is represented as:

$A = A_o * (1/2)^{t/h}$

Where

Ao represents the initial amount

So, we have:

$A = 5 * (1/2)^{t/2}$

In 4 years, t = 4.

So, we have:

$A = 5 * (1/2)^{4/2}$

This gives

$A = 5 * (1/2)^2$

Evaluate the expression

A = 1.25

Hence, the remaining amount after 4 years is 1.25 kg

Read more about half life at:brainly.com/question/26148784

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