Question

ASSIGNMENT

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

26

Explanation:

$\int\limits^{25}_{-1} {e^{x-[x]}} \, dx$

simplify

$\int\limits^{25}_{-1} {e^{0} \, dx$

any variable to the power 0 is 1

$\int\limits^{25}_{-1} 1 \, dx$

integrating 1 gives x

$\left[ \:x \: \right]^{25}_{-1}$

apply limits

$25 - (-1)$

add terms

$26$