Find the integral ∫(cos(1/x)) /x^2 dx

Mathematics

1 answer:

melisa1 [442]2 years ago

4 0

Answer:

Step-by-step explanation:

∫(cos(1/x)/x² dx

$put~\frac{1}{x} =t\\diff.\\\frac{-1}{x^2} dx=dt\\\int(- cos~t~)dt=-sin~t+c\\=-sin (\frac{1}{x} )+c$

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