Question

Find the integral ∫(cos(1/x)) /x^2 dx

Answer 1

Answer:

Step-by-step explanation:

∫(cos(1/x)/x² dx

$put~\frac{1}{x} =t\\diff.\\\frac{-1}{x^2} dx=dt\\\int(- cos~t~)dt=-sin~t+c\\=-sin (\frac{1}{x} )+c$