Answer:
(a) P(A1 ∪ A2) = 0.35
Step-by-step explanation:
(a) A1 ∪ A2 :
We start by defining the events.
A1 : '' awarded project 1''
A2 : ''awarded project 2''
A3: ''awarded project 3''
In set theory we write the union of events A and B as A∪B.
A∪B means that the event A occurs,event B occurs or either both events occurs at the same time.
The probability is given by the equation :
P(A∪B) = P(A) + P(B) - P(A∩B) (1)
Where the event (A∩B) is the event where A and B occur at the same time
and P(A∩B) is the probability of (A∩B)
Using the equation (1) :
P(A1 ∪ A2) = P(A1) + P(A2) - P(A1∩A2)
P(A1 ∪ A2) = 0.22 + 0.25 - 0.12
P(A1 ∪ A2) = 0.35
Answer:
k=7
Step-by-step explanation:
first, plug in the given values
2x+3y=k --> 2(2)+3(1)=k
-->4+3=k
-->7=k
k=7
Answer:
(a) Output = 37
(b) Input = 9
Step-by-step explanation:
Given

Solving (a): Output, when input = 8
This means that, we solve for y when x = 8
So, we have:




Solving (b): Input, when output = 42
This means that, we solve for x when y = 42
So, we have:


Collect like terms


Divide both sides by 5

Given:
Consider the given equation is

To find:
The solution of the equation for l.
Solution:
We have,

Substract 2W from both sides.


Divide both sides by 2.



Therefore, the correct option is 3.
Check the picture below, so the parabola looks more or less like so, hmmm with a vertex at (-1 , -4), so, using those values from the table
![~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=~~~~~~%5Ctextit%7Bvertical%20parabola%20vertex%20form%7D%20%5C%5C%5C%5C%20y%3Da%28x-%20h%29%5E2%2B%20k%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22a%22~is~negative%7D%7Bop%20ens~%5Ccap%7D%5Cqquad%20%5Cstackrel%7B%22a%22~is~positive%7D%7Bop%20ens~%5Ccup%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\stackrel{vertex}{\stackrel{h}{-1}~~,~~\stackrel{k}{-4}}\qquad \implies y=a[x-(-1)]^2-4\implies y=a(x+1)^2-4 \\\\\\ \textit{we also know that} \begin{cases} x=2\\ y=14 \end{cases}\implies 14=a(2+1)^2-4\implies 18=9a \\\\\\ \cfrac{18}{9}=a\implies 2=a~\hspace{10em}\boxed{y=2(x+1)^2-4}](https://tex.z-dn.net/?f=%5Cstackrel%7Bvertex%7D%7B%5Cstackrel%7Bh%7D%7B-1%7D~~%2C~~%5Cstackrel%7Bk%7D%7B-4%7D%7D%5Cqquad%20%5Cimplies%20y%3Da%5Bx-%28-1%29%5D%5E2-4%5Cimplies%20y%3Da%28x%2B1%29%5E2-4%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Bwe%20also%20know%20that%7D%20%5Cbegin%7Bcases%7D%20x%3D2%5C%5C%20y%3D14%20%5Cend%7Bcases%7D%5Cimplies%2014%3Da%282%2B1%29%5E2-4%5Cimplies%2018%3D9a%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B18%7D%7B9%7D%3Da%5Cimplies%202%3Da~%5Chspace%7B10em%7D%5Cboxed%7By%3D2%28x%2B1%29%5E2-4%7D)