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wel
2 years ago
9

If a fair coin is tossed four times, what is the probability of it landing heads up at least three times

Mathematics
1 answer:
garri49 [273]2 years ago
4 0

The probability of it landing heads up at least three times is 1/4.

According to the statement

We have a given that the coin is tossed 4 times And we have to find the probability of it landing heads up at least three times.

So, we know that the

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1.

So, According to the statement

Coin is tossed 4 times and we have to probability of find heads three times it means n = 3.

To get 3 heads, means that one gets only one tail. This tail can be either the 1st coin, the 2nd coin, the 3rd, or the 4th coin.

Thus there are only 4 outcomes which have three heads.

The probability is 4/16 = 1/4.

So, The probability of it landing heads up at least three times is 1/4.

Learn more about the probability here brainly.com/question/24756209

#SPJ4

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Answer: 12.9

Step-by-step explanation:

lThe area of the triangles is 3/2 x 2.6 = 3.9/2 = 1.95. since there is 2 triangle do 1.95 x 2 = 3.9. and the area of the square is 3x3 = 9. All in all, 3.9 + 9 = 12.9.

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3 years ago
I just can't figure this out. Please help me solve this step by step.
maxonik [38]

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Step-by-step explanation:

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5 0
3 years ago
The length of a rectangle is 3 times the width. The perimeter is 44 cm. What are the dimensions of the rectangle? Write and solv
ser-zykov [4K]
Here are your equations:
x and 3x
How to set up:
2(x)+ 2(3x) = 44
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5 0
3 years ago
The Environmental Protection Agency (EPA) has contracted with your company for equipment to monitor water quality for several la
max2010maxim [7]

Answer:

36.58% probability that one of the devices fail

Step-by-step explanation:

For each device, there are only two possible outcomes. Either it fails, or it does not fail. The probability of a device failling is independent of other devices. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A total of 15 devices will be used.

This means that n = 15

Assume that each device has a probability of 0.05 of failure during the course of the monitoring period.

This means that p = 0.05

What is the probability that one of the devices fail?

This is P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{15,1}.(0.05)^{1}.(0.95)^{14} = 0.3658

36.58% probability that one of the devices fail

7 0
3 years ago
All i have to say it help pls
Lemur [1.5K]

Answer:

The answer is n=-5!

Step-by-step explanation:

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8 0
3 years ago
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