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2 years ago

15

For 2-3, Name a postulate or theorem that can be used to prove that the two triangles are similar. Then, write a similarity stat

ement.

1 answer:

lilavasa [31]2 years ago

6 0

Postulate: AA

Similarity statement: $\triangle CBA \sim \triangle FED$

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A. Isosceles <br> B. Right <br> C. Equilateral <br> D. Obtuse

zubka84 [21]

Answer:

D. Obtuse

Step-by-step explanation:

Although it could be an equilateral triangle. You are just looking at ABC so disregard all other triangles.

4 0

4 years ago

Read 2 more answers

3. Factor by identifying a common factor in each term.

Anastasy [175]

Answer:

$\large\boxed{g)\ 6xy^2=(3x)(2y^2)}\\\boxed{h)\ 25a^3b^2=(5a^2b^2)(5a)}\\\boxed{i)\ 6x+6y+6p=6(x+y+p)}$

Step-by-step explanation:

$g)\ 6xy^2=3\cdot2\cdot x\cdot y\cdot y=(3\cdot x)(2\cdot y\cdot y)=(3x)(2y^2)\\\\h)\ 25a^3b^2=5\cdot5\cdot a\cdot a\cdot a\cdot b\cdot b=(5\cdot a\cdot a\cdot b\cdot b)(5\cdot a)=(5a^2b^2)(5a)\\\\i)\ 6x+6y+6p=6\cdot x+6\cdot y+6\cdot p=6(x+y+p)$

Other way for g) and h):

$g)\ \dfrac{6xy^2}{3x}=\dfrac{6}{3}\cdot\dfrac{xy^2}{x}=2y^2\\\\6xy^2=(3x)(2y^2)\\\\h)\ \dfrac{25a^3b^2}{5a^2b^2}=\dfrac{25}{5}\cdot\dfrac{a^3}{a^2}\cdot\dfrac{b^2}{b^2}=5a\\\\25a^3b^2=(5a^2b^2)(5a)$

6 0

3 years ago

The choices are <br> 1. No<br> 2. Yes

pentagon [3]

Answer:

Yes

Step-by-step explanation:

equal distance from the center on both sides

5 0

3 years ago

Which equation represents a circle that contains the point (-5,-3) and has a center at (-2,1)

MatroZZZ [7]

Answer:

The equation of circle is:

Solution:

The general form of equation is given as:

Where, "r" is radius of circle and (a, b) is center of circle

Given that center at (-2, 1)

a = -2 and b = 1

Substitute (a , b) = (-2, 1) and (x, y) = (-5, -3) in general equation

Substitute r = 5 and (a, b) = (-2, 1) in general equation

Thus the equation of circle is found

4 0

4 years ago

From the following figure, why can you not conclude that lines l and m are parallel?

vichka [17]

Answer:

A

Step-by-step explanation:

For the lines to be parallel then the 2 corresponding angles would have to be congruent. However, they are not , one is 120 the other is 118

Hence corresponding angles postulate are not congruent.

8 0

3 years ago

Read 2 more answers