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2 years ago

Given the drawing as shown below and that plla, name a pair of

Mathematics

1 answer:

Kipish [7]2 years ago

4 0

Answer:

Angle D & Angle E

Step-by-step explanation:

Angle C & Angle F are ALTERNATE EXTERIOR angles.

Angle B & Angle E are CONSECUTIVE angles.

Angle D & Angle G are CORRESPONDING angles.

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mixas84 [53]

Answer:

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Step-by-step explanation:

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3 years ago

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jarptica [38.1K]

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8 0

3 years ago

Read 2 more answers

Solve 5x2 = −30x − 65. x = −3 ± 2i x = −3 ± 4i x = −6 ± 2i x = −6 ± 4i

Vladimir [108]

The answer is -6 -/+ 4i. Hope this helps.

8 0

3 years ago

If y = 6x - 4 which of the following sets represents possible inputs and outputs of the function represented as ordered pairs?

noname [10]

The only of these that is a proper set of ordered pairs for this equations is A) (0,-4) (1,2) (3,14)

In order to prove this, you need to put each ordered pair into the equation and prove that it is a true statement. Below are the examples of this for A.

(0, -4)

y = 6x - 4

-4 = 6(0) - 4

-4 = 0 - 4

-4 = -4 (TRUE)

(1, 2)

y = 6x - 4

2 = 6(1) - 4

2 = 6 - 4

2 = 2 (TRUE)

(3, 14)

y = 6x - 4

14 = 6(3) - 4

14 = 18 - 4

14 = 14 (TRUE)

Therefore, each of these ordered pairs works in the equation.

7 0

3 years ago

Suppose a football player kicks a ball and gives it an initial upward velocity of 47 ft/s. Use the formula h(t)= -16t^2+47t+3 wh

statuscvo [17]

Answer:

Step-by-step explanation:

a. when t=0,h=3ft

$h(t)=-16 (t^2-\frac{47}{16}x+(\frac{47}{32} )^2)+\frac{47^2}{32^2} *16+3\\=-16(t-\frac{47}{32})^2+\frac{2209}{64}+3\\=-16(t-\frac{47}{32})^2+\frac{2209+192}{64}\\when~ t=\frac{47}{32}\\h=\frac{2301}{64}\\or~v^2-u^2=2gh\\\\0^2-47^2=2*(-32)h\\or h=\frac{47^2}{64}=\frac{2209}{64} \\height from the ground=\frac{2209}{64} +3=\frac{2301}{64}$

c.t=47/32 sec

time taken to fall 2301/64 ft=0*t+\frac{1}{2}*32*t^2

t^2=\frac{2301}{64*16}

t=\frac{\sqrt{2301}}{8*4}=\frac {47.97}{32}

total ~time=\frac{47+47.97}{32}=\frac{94.97}{32} sec

4 0

3 years ago