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natali 33 [55]
3 years ago
7

K(x) = 6x + 100 k(-5) =

Mathematics
2 answers:
LekaFEV [45]3 years ago
8 0
K(-5)=70
I hope that helps buddy
Mars2501 [29]3 years ago
7 0

Answer:

k(- 5) = 70

Step-by-step explanation:

To evaluate k(- 5) substitute x = - 5 into k(x)

k(- 5) = 6(- 5) + 100 = - 30 + 100 = 70

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In a simple random sample of 1500 young Americans 1305 had earned a high school diploma.
inn [45]

Answer:

a) The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.

b) The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.

c) The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).

d) The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Standard error:

The standard error is:

s = \sqrt{\frac{\pi(1-\pi)}{n}}

Margin of error:

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = zs

The confidence interval is:

Sample proportion plus/minus margin of error. So

(\pi - M, \pi + M)

In a simple random sample of 1500 young Americans 1305 had earned a high school diploma.

This means that n = 1500, \pi = \frac{1305}{1500} = 0.87

a. What is the standard error for this estimate of the percentage of all young Americans who earned a high school diploma?

s = \sqrt{\frac{\pi(1-\pi)}{n}} = \sqrt{\frac{0.87*0.13}{1500}} = 0.0087

0.0087*100% = 0.87%.

The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.

b. Find the margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Then

M = zs = 1.96*0.0087 = 0.0171

0.0171*100% = 1.71%

The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.

c. Report the 95% confidence interval for the percentage of all young Americans who earned a high school diploma.

87% - 1.71% = 85.29%

87% + 1.71% = 88.71%.

The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).

d. Suppose that in the past, 80% of all young Americans earned high school diplomas. Does the confidence interval you found in part c support or refute the claim that the percentage of young Americans who cam high school diplomas has increased? Explain.

The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.

4 0
3 years ago
Put this numbers from least to greatest.
Tanzania [10]

Answer:

0.651, 0.67, 1.79, 3.2, and 9

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Question 14 of 25
Vlad1618 [11]
The answer is B, Hope this helps ! :)
8 0
1 year ago
Also if I can I give brainiest answer to first person
postnew [5]

Answer:

the answer is 22

the equation is 30 + 15n

Step-by-step explanation:

15n as it increases each month and 30 as it never changes and will always be a value of 30

8 0
2 years ago
Read 2 more answers
The Toy Company sells two types of kids' basketball hoops, Jordan size and Shaq size.
Hoochie [10]

Answer:

Maximum Profit = 13050

when

The Toy company sells Jordan Size hoops = 7

The Toy company sells Shaq Size hoops = 3

Step-by-step explanation:

Given - The Toy Company sells two types of kids' basketball hoops, Jordan size and Shaq size.  A neighborhood needs no more than 10 Jordan sizes and Shaq sizes all together. The  Company requires the neighborhood to order at least 2 Jordan sizes and at least 3  Shaq sizes. The Toy Company makes a profit of $1,350 on the Jordan size and $1,200  on the Shaq size.

To find - What is the maximum profit they can make given the constraints  above?

Proof -

Let us assume that,

The Toy company sells Jordan Size hoops = x

The Toy company sells Shaq Size hoops = y

Now,

Given that,  A neighborhood needs no more than 10 Jordan sizes and Shaq sizes all together.

⇒x + y ≤ 10

Now,

Given that,  The  Company requires the neighborhood to order at least 2 Jordan sizes and at least 3  Shaq sizes.

⇒ x ≥ 2

   y ≥ 3

Now,

Given that,

The Toy Company makes a profit of $1,350 on the Jordan size and $1,200  on the Shaq size.

So,

The objective function becomes

Z = 1350x + 1200 y

So,

The Linear Programming Problem (LPP) becomes

Maximize Z = 1350x + 1200 y

Subject to

x + y ≤ 10

x ≥ 2

y ≥ 3

x, y ≥ 0

We will Solve the LPP by Graphical method.

The graph is as follows :

The points on the Boundary are -

A(2, 8)

B(2, 3)

C(7, 3)

So,

Points (x,y) Objective function value  ( Z = 1350x + 1200y)

B(2,3)            1350(2) + 1200(3) = 6300

C(7,3)           1350(7) + 1200(3) = 13050

A(2,8)                 1350(2) + 1200(8) = 12300

So,

Maximum value = 13050 at point C(7,3)

∴ we get

Maximum Profit = 13050

when

The Toy company sells Jordan Size hoops = x = 7

The Toy company sells Shaq Size hoops = y = 3

6 0
3 years ago
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