Question

Find the zeros of the following please solve step by step 1. x³+9x²+26x+24=0

Answer 1

Answer: -4, -3, -2

Step-by-step explanation:

By inspection, we know $x=-2$ is a root.

We can thus rewrite the equation as

$(x+2)\left(\frac{x^3 + 9x^2 + 26x+24}{x+2} \right)=0\\\\(x+2)(x^2 + 7x+12)=0\\\\(x+2)(x+3)(x+4)=0\\\\x=-4, -3, -2$