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mezya [45]
2 years ago
15

The graphs of f(x) = 5x and its translation, g(x), are

Mathematics
1 answer:
HACTEHA [7]2 years ago
5 0

Answer: g(x)=5^x - 10

Step-by-step explanation:

g(x) is the graph of f(x) translated 10 units down.

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Lily is going for a run. she runs at a speed of 4 miles per hour for 6.4
Nezavi [6.7K]

Answer:

She runs for 1.6 hours

Step-by-step explanation:

For this, one way to do it is to just set 1 hour over 4 miles equal to x hours for 6.4 miles. The reason this is done is because if the speed is constant that means the rate stays the same, which means the ratio of miles to hours should always be the same, so the two ratios must be equivalent.

1/4 = x/6.4

Multiply both sides by 6.4 to get x by itself:

6.4/4 = x

1.6 = x

Hope that helps!

4 0
4 years ago
Find the slope of the line that passes through the points
lesantik [10]

Answer: 1/8

Step-by-step explanation:

1 - 0 = 1

0 - 8 = 8

m = 1/8

3 0
3 years ago
Help pleasee I don’t get it
max2010maxim [7]

Answer:

no they're not congruent

8 0
3 years ago
In a solar system, two comets pass near the sun, which is located at the origin. Comet E is modeled by quantity y plus 16 end qu
Leya [2.2K]

Explanation:

The equation of comet E is given below as

\frac{(y+16)^2}{400}+\frac{x^2}{144}=1

The equation of comet H is modelled below as

\frac{(y+13)^2}{144}-\frac{x^2}{25}=1

Given, that the Sun is located at the origin.

This is an equation of an ellipse. So, the path traveled by Comet e is an elliptic path.

Comparing with the Standard equation of ellipse: below,we will have

\frac{(y-k)^2}{b^2}+\frac{(x-h)^2}{a^2}

Whise center is

\begin{gathered} center=(h,k) \\ vertices=(h\pm a,0) \end{gathered}

By comparing coefficient, we will have

\begin{gathered} a^2=144 \\ a=12 \\ b^2=400 \\ b=20 \\ k=-16 \\ h=0 \\ (h,k)=(0,-16) \end{gathered}

Hence,

The vertex of comet E will be

\begin{gathered} (h\pm a,0) \\ (0+12,0),(0-12,0) \\ (12,0),(-12,0) \end{gathered}

The vertex of comet E is

(12,0),(-12,0)

Part C:

It is the foci forboth comets

\begin{gathered} cometE: \\ c=\sqrt{b^2-a^2} \\ c=\sqrt{400-144} \\ c=\sqrt{256} \\ c=16 \\  \\ For\text{ comet F:} \\ c=\sqrt{a^2-b^2} \\ c=\sqrt{144+25} \\ c=\sqrt{169} \\ c=13 \end{gathered}

Hence,

The foci will be

\begin{gathered} (16\pm16,0) \\ cometE \\ (0,0),(32,0) \\ cometF: \\ (13\pm13,0) \\ (0,0),(26,0) \end{gathered}

5 0
1 year ago
Solve for v.<br> 5(v+2) = -2(7v-3) +9v<br> Simplify your answer as much as possible
Andreas93 [3]

5(v+2) = -2(7v-3) + 9

------------------------------------

Distribute:

5v + 10 = -14v + 6 + 9

Combine Like Terms

5v + 10 = (-14v+9v)+6

5v + 10 = -5v + 6

Subtract -5v from both sides

10v + 10 = 6

Subtract 10 from both sides

10v = -4

Reduce

5v = -2

Divide both sides by 5

v = -2/5

Simplify

v = -0.2

3 0
4 years ago
Read 2 more answers
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