Question

Suppose we want to choose 2 colors, without replacement from 3 colors red blue and green how many ways can this be done in the order of the choice is relevant and not relevant

Answer 1

The two colors can be chosen in 3 different ways.

In how many ways can we choose two colors?

If we have a set of N elements, the number of different sets of K elements (such that the order of the K elements does not matter) is:

$C(N, K) = \frac{N!}{(N - K)!*K!}$

In this case, we have 3 colors, so N=3, and we want to choose 2, then K=2.

Replacing that we get:

$C(3, 2) = \frac{3!}{(3- 2)!*2!} = \frac{3*2*1}{1*2*1} = 3$

The two colors can be chosen in 3 different ways.

If you want to learn more about combinations:

brainly.com/question/11732255

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