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2 years ago

ANSWER ASAP!

Mathematics

1 answer:

fenix001 [56]2 years ago

5 0

The sequence of the ball is 3, 1, 1/3, 1/9,...

<h3>How to find terms of a sequence?</h3>

The ball starts bouncing with a height of 3 feet.

Each bounce reaches a third of the height of the previous bounce.

Therefore,

a = first term = 3

r = common ratio = 1 / 3

Therefore,

nth term = arⁿ⁻¹

where

a = first term
r = common ratio
n = number of terms

First term = 3

2nd term = 3 × (1 / 3) = 1

Third term = 3 × (1 / 3)² = 1 / 3

Fourth term = 3 × (1 / 3)³ = 1 / 9

Therefore, the sequence of the ball is 3, 1, 1/3, 1/9,...

learn more on sequence here: brainly.com/question/13042200

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In 1990, 23.8% of 18-24 year-olds in Biddeford, Maine were attending college. About 10 years later, a random sample of 610 18-24

Vlada [557]

Answer:

There is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 610

p = 23.8% = 0.238

Alpha, α = 0.01

Number of 18-24 year-old attending college , x = 178

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.238\\H_A: p > 0.238$

This is a one-tailed(right) test.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{178}{610} = 0.2918$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.2918-0.238}{\sqrt{\frac{0.238(1-0.238)}{610}}} = 3.1201$

Now, we calculate the p-value from the table.

P-value = 0.0009

Since the p-value is lower than the significance level, we fail to accept the null hypothesis and reject the null hypothesis.

Conclusion:

Thus there is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

4 0

4 years ago

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The graph (shown in red) below shows the solution set of which inequality?

Elina [12.6K]

Answer:

Step-by-step explanation:

The red portion shows all numbers GREATER THAN or EQUAL TO 0.

So that would be x ≥ 0

<em>Looking at the answer choices, there is no "x", rather "√x"</em>

<em>To make it "x", we need to square both sides and the option C wouldn't make a difference. Shown below:</em>

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<em>Option C is right.</em>

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3 years ago

I WILL REWARD BRAINLIEST

aksik [14]

Answer:

Answer: What is the total number of students who brought water bottles to lunch?

A statistical question is a question with data that will vary.

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3 years ago

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3/7 as a percentage (closest as possible)

3241004551 [841]

Answer:

your answer will be 42.857143%

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3 years ago

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3. Two of the vertices of an equilateral triangle are (0, -a)

egoroff_w [7]

The third coordinate of the equilateral triangle is $(\sqrt3a,0)$ . Ir can be obtained by distance formula.

What is distance formula?

It gives the distance between two coordinates.

Distance formula is given by the following expression:

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Consider the third cordinate is (x,0) and x is positive because it is on tight side on the x axis.

Now, since the triangle is equilateral hence, the distance of (x,0) from (0, -a) and (0, a) should be equal to distance between (0, -a) and (0, a).

Now, caculate the distance between (0,-a) and (0, a). $\sqrt{(0-0)^2+(-a-a)^2}=2a$

Now, distance between (x,0) and (0, a) should be 2a.

$\sqrt{(x-0)^2+(0-a)^2}=2a\\\sqrt{x^2+a^2}=2a$

Now, square on both the sides.

$x^2+a^2=4a^2\\x^2=3a^2\\x=\sqrt3a$ and $-\sqrt3a$

But the negative value of x is not possible because the coordinate lies on the right side.

Hence, the third coordinate of equilateral triangle is $(\sqrt3a,0)$ .

Learn more about distance formula from the following link:

brainly.com/question/7243416

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5 0

1 year ago