The amount more of rain that fell in those three days than normally falls in July and August combined was 31.19 cm.
<h3>How much more rain fell in those three days?</h3>
The amount of rain in those three days was 41.2 cm.
The combined normal rain July and August is:
= 6.36 + 3.65
= 10.01 cm
The difference is therefore:
= 41.2 - 10.01
= 31.19 cm
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Answer:
equation: y = 4x-12
slope: 4
y-intercept: -12
Step-by-step explanation:
3 points across an x-axis is +1 x-axis difference and +4 y-axis away from origin, so you have to subtract 3 by 1 andsubtract y by 4. until x is 0, you get -12 on y-axis
Answer:
12.92%
Step-by-step explanation:
Mean of the scores= u = 500
Standard deviation =
= 10.6
We have to find what proportion of students scored more than 512 marks.
The distribution of scores in a test generally follows the Normal distribution. So we can assume that the distribution of MCAT scores is normally distributed about the mean.
Since, the distribution is normal, we can use the concept of z scores to find the proportion of students who scored above 512.
The formula for z scores is:

So, z score for x = 512 will be:

Thus,
P(X > 512) is equivalent to P(z > 1.13)
So, the test scores of 512 is equivalent to a z score of 1.13. Using the z table we have to find the proportion of z scores being greater than 1.13, which comes out to be 0.1292
Since,
P(X > 512) = P(z > 1.13)
We can conclude that, the proportion of students taking the MCAT who had a score over 512 is 0.1292 or 12.92%
We will start with plotting the x coordinates and y coordinates on the graph
The points 1, 2; 2, 2; 3, 2; 4, 2 have been plotted on the graph which has been attached as an image to the solution.
We can see that the value of y is staying constant (2) for all values of x.
Hence, the points represent the equation y = 2.