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MA_775_DIABLO [31]
2 years ago
7

Find the decimal. _. _ _ _ Clues: (a) The digits 0, 1 and 2 are not used in the decimal. (b) The digit in the ones place is the

greatest 1-digit number. The hundredths digit is smaller than 5. The difference between the tenths digit and the ones digit is the hundredths digit. (c) (d) (e) (f) The thousandths digit is greater than 5 and is an odd number. All the digits are different.​
Mathematics
1 answer:
const2013 [10]2 years ago
6 0

Answer:

Step-by-step explanation:

143

or

121

We are accepting

does any of this help

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C

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g(x)=1/3 |x|

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Can y’all help me on question 11?!
Free_Kalibri [48]

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B and D

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B.

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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

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