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Sergeeva-Olga [200]
1 year ago
8

HELP HELP HELP HELP HELP HELP HELP HELP

Mathematics
1 answer:
Lelechka [254]1 year ago
5 0

Answer:

Vertex - (2, -1)

Axis of Symmetry - x = 2

X intercept - (3,0) (1, 0)

Y intercept (0, 3)

Domain - (negative infinity, positive infinity)

Range - [-1, infinity)

Step-by-step explanation:

I graphed with desmos and found it.

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Answer:

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Step-by-step explanation:

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2 years ago
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What value of c makes the polynomial below a perfect square? x^2+10+c
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Answer: Hi there

To find the last term in order to obtain the perfect square, take the middle term, divide it by 2, and take its square. 

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sertanlavr [38]
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3 years ago
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I’m need this worked out step by step by tonight
Pie

9514 1404 393

Answer:

  -3 ≤ x ≤ 19/3

Step-by-step explanation:

This inequality can be resolved to a compound inequality:

  -7 ≤ (3x -5)/2 ≤ 7

Multiply all parts by 2.

  -14 ≤ 3x -5 ≤ 14

Add 5 to all parts.

  -9 ≤ 3x ≤ 19

Divide all parts by 3.

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_____

<em>Additional comment</em>

If you subtract 7 from both sides of the given inequality, it becomes ...

  |(3x -5)/2| -7 ≤ 0

Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.

__

For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...

  |f(x)| < (some number) . . . . or ≤

If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:

  |f(x)| > g(x)   ⇒   f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0

Any solutions to these inequalities must respect their domains.

8 0
2 years ago
What kind of angle pair do they create?
Bond [772]

Answer:

They create supplementary angle pairs.

Step-by-step explanation:

Supplementary angles add up to 180°.

8 0
3 years ago
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