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2 years ago

Shortest distance between two atoms in proteins without any bonding

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1 answer:

Lemur [1.5K]2 years ago

5 0

The shortest distance between two (2) atoms in proteins without any bonding is typically 2 to 70 nanometer.

<h3>What is a protein?</h3>

A protein can be defined as an hydrophilic, macromolecule (polymer) that is formed due to the union of a chain of amino acids.

Based on scientific records and information, we can infer that the shortest distance between two (2) atoms in proteins without any bonding typically ranges from 2 to 70 nanometer.

Read more on protein here: brainly.com/question/19145247

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The vertices of square cdef are c(1, 1), d(3, 1), e(3,−1) and f(1,−1). Which of the following shows that its diagonals are congr

maks197457 [2]

The equation $-1 = -\frac {1}{1}$ shows that the diagonals are congruent perpendicular bisectors.

The vertices of the square are given as:

c = (1,1)
d = (3,1)
e =(3,-1)
f = (1,-1)

<h3>How to determine the congruent perpendicular bisectors.</h3>

Start by calculating the slope of diagonal ce using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$m = \frac{-1-1}{3 -1}$

$m = \frac{-2}{2}$

$m_1 = -1$

Next, calculate the slope of diagonal df using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$m = \frac{-1-1}{1-3}$

$m = \frac{-2}{-2}$

$m_2 = 1$

The slopes of both diagonals are:

$m_1 = -1$

$m_2 = 1$

By comparing both slopes, we have:

$m_1 = -\frac {1}{m_2}$

i.e.

$-1 = -\frac {1}{1}$

Hence, $-1 = -\frac {1}{1}$ shows that the diagonals are congruent perpendicular bisectors.

Read more about perpendicular bisectors at:

brainly.com/question/11006922

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Answer:

5:8 i think

Explanation:

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