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Wittaler [7]
2 years ago
10

Zhang is constructing a loading ramp (BA) that is 4-feet high (AC). The back of the base (BC) must be 12.8 ft. How long must the

entire base (BD) be?
Proportion : __________________

Front of base: __________

Total base: __________

Mathematics
1 answer:
inna [77]2 years ago
6 0

The front of the base is 1.25 ft and the total base is 14.05 ft.

<h3>How to find the side of a right triangle?</h3>

A right triangle has one of its angles as 90 degrees. The side of a right angle triangle can be found using trigonometric ratios.

The sides CD and BD can be found using similar triangle principle.

In similar triangles, corresponding sides are always in the same ratio.

Therefore, the following proportion can be established as follows;

\frac{BC}{AC}=\frac{AC}{CD}

Hence,

\frac{12.8}{4}=\frac{4}{CD}

cross multiply

4 × 4 = 12.8 CD

16 = 12.8CD

divide both sides by 12.8

CD = 16 / 12.8

CD = 1.25 ft

BD = 1.25 + 12.8 = 14.05 ft

Therefore, the front of the base is 1.25 ft and the total base is 14.05 ft.

learn more on right triangle here: brainly.com/question/14324872

#SPJ1

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Answer:

1.  36

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4. The perimeter is the distance around the object while the area is the amount of space inside the area.

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The selling price of a house dropped from $250,000 to $210,000 over a period of 5 years.
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3 years ago
7x(x+1.8)=0<br> 7x(x+1.8)=0<br> 7x(x+1.8)=0 <br> Answer those 3
ahrayia [7]

Answer:

The answer to all of those questions would be x=-1.8

Step-by-step explanation:

7x(x + 1.8) = 0 - Distribute through the Parenthesis -

7x^2 + 12.6x = 0

x(7x + 12.6) = 0


x = 0


7x + 12.6 = 0

7x = -12.6

x = -12.6/7

x = -1.8


so x = 0 or x = -1.8

3 0
3 years ago
A survey of high school juniors found the 75% of the students plan on attending college. If you pick 3 students at random, what
olya-2409 [2.1K]

Assuming you pick 3 students at random, The probability that at least two plan on attending college is 84%.

<h3>Probability</h3>

Using Binomial Distribution

Given:

n = 3

p = 0.75

q = 1-0.95 = 0.25

Hence:

P[≥2] = P[2] + P[3]=(3c2 ×0.75²×0.25) + 0.75³

P[≥2] = P[2] + P[3]=0.421875+0.421875

P[≥2] = P[2] + P[3]=0.84375×100

P[≥2] = P[2] + P[3]=84% (Approximately)

Inconclusion the probability that at least two plan on attending college is 84%.

Learn more about probability here:brainly.com/question/24756209

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