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Mademuasel [1]
2 years ago
12

Solve for x in the equation x squared 11 x startfraction 121 over 4 endfraction = startfraction 125 over 4 endfraction.

Mathematics
1 answer:
Mrrafil [7]2 years ago
6 0

The solutions are { -1,-11}

Lets solve the given equation:

x^2 + 11x + 121/4 = 125/4

Subtracting 125/4 from both sides:

=>x^2 + 11x + 121/4-125/4= 125/4 -125/4

=> x^2 + 11x - (-4/4) = 0

=> x^2 +11x -(-1) = 0

=>x^2 + 11 x + 1 = 0

This is a quadratic equation so we will use the determinant (b^2-4ac)

a = 1

b = 11

c = 1

b^2-4ac = 11^2-4*1*1 = 117

So this equation has two solutions:

x = (-b -/+ √(b^2-4ac) ) / 2a

x = (-11 -/+ √(117) ) / 2

x = (-11 -/+ 3√(13))/ 2

x = -0.91 or x = -10.9

x = -1 or x = -11 ( rounding off)

hence the solutions are { -1,-11}.

Learn more about Quadratic Equation on:

brainly.com/question/1214333

#SPJ4

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