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Ket [755]
2 years ago
12

Given IQ scores are approximately normally distributed with a mean of 100 and a standard deviation of 15, the proportion of peop

le with IQs above 130 is
Mathematics
1 answer:
weeeeeb [17]2 years ago
8 0

The proportion of people with IQs above 130 is 2.3%.

<h3>How to calculate the value?</h3>

Normal distribution, is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.

Here the mean is 100 and a standard deviation of 15.

µ = 100, σ = 15

P(X > 130) =

= P( (X-µ)/σ > (130-100)/15)

= P(z > 2)

= 1 - P(z < 2)

Using excel function:

= 1 - NORM.S.DIST(2, 1)

= 0.023 = 2.3%

The value is 2.3%.

Learn more about proportion on:

brainly.com/question/19994681

#SPJ1

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What is the range of the function on the graph
Tanzania [10]

Answer:

All real numbers greater than or equal to -2.

Step-by-step explanation:

The range is the set of values of the y-coordinates of the points on the graph.

The smallest y-coordinate is -2. All real numbers greater than equal to -2 are the range.

Answer: All real numbers greater than or equal to -2.

6 0
3 years ago
Find the flux of F = x^3 i  + y^3 j  + z^3k through the closed surface bounding the solid region x^2 + y^2 ≤ 4, 0 ≤ z ≤ 4
givi [52]
Use the divergence theorem. Let R be the cylindrical region, then

\displaystyle\iint_{\partial R}\mathbf F\cdot\mathbf n\,\mathrm dS=\iiint_R\nabla\cdot\mathbf F\,\mathrm dV

(where \mathbf n denotes the unit normal vector to \partial R, but we don't need to worry about it now)

We have

\mathrm{div }\mathbf F=(\nabla\cdot\mathbf F)(x,y,z)=\dfrac{\partial\mathbf F}{\partial x}+\dfrac{\partial\mathbf F}{\partial y}+\dfrac{\partial\mathbf F}{\partial z}
\nabla\cdot\mathbf F=3x^2+3y^2+3z^2

For the solid R with boundary \partial R, we can set up the following volume integral in cylindrical coordinates for ease:

\displaystyle3\iiint_R(x^2+y^2+z^2)\,\mathrm dV=3\int_{z=0}^{z=4}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=2}(r^2+z^2)r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz
=\displaystyle6\pi\int_{z=0}^{z=4}\int_{r=0}^{r=2}(r^3+rz^2)\,\mathrm dr\,\mathrm dz
=\displaystyle12\pi\int_{z=0}^{z=4}(2+z^2)\,\mathrm dz
=352\pi
5 0
3 years ago
A system of identifying call letters uses call letters that begin either with E or W. Some have a total of 2 letters, and others
Klio2033 [76]

Answer:

If repetition is allowed then the different call letters possible are 1404.

If repetition is allowed then the different call letters possible are 1250.

Step-by-step explanation:

The call letter are of either 2 letter or 3 letters.

And for them to be identified they should start with either E or W.

  • If Repetition is allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : <u>E</u> _

The second place can be filled any of the 26 letters.

Possible number of call letters starting with W : <u>W</u> _

The second place can be filled any of the 26 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : <u>E</u> _ _

The second place and third place can be filled with any of the 26 letters.

Possible number of call letters starting with W : <u>W</u> _ _

The second place and third place can be filled with any of the 26 letters.

Total number of possible letters: 26 + 26 + (26)² + (26)² = 1404

Thus, if repetition is allowed then the different call letters possible are 1404.

  • If Repetition is not allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : <u>E</u> _

The second place can be filled any of the 25 letters.

Possible number of call letters starting with W : <u>W</u> _

The second place can be filled any of the 25 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : <u>E</u> _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Possible number of call letters starting with W : <u>W</u> _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Total number of possible letters: 25 + 25+ (25 × 24) + (26 × 24) = 1250

Thus, if repetition is allowed then the different call letters possible are 1250.

5 0
3 years ago
08.01)Marlow wants to know how many students in his school enjoy watching the TV news. He asks all 27 students in his art class
Inga [223]
Part 1 : Marlow wants to know how many students in his school enjoy watching the TV news. He asks all 27 students in his art class and finds that 30% of his classmates enjoy watching the TV news. He claims that 30% of the school's student population would be expected to enjoy watching the TV news. Is Marlow making a valid inference about his population?

No, it is not a valid inference because he asked all 27 students in his art class instead of taking a sample from the school

No, it is not a valid inference because his classmates do not make up a random sample of the students in the school

Yes, it is a valid inference because he asked all 27 students in his art class

Yes, it is a valid inference because his classmates make up a random sample of the students in the school 

Answer = The correct answer is <span>B because Marlow was supposed to ask random kids and they were not suppose to be in his class. 

Part 2 : </span><span>Carl takes a random sample of 100 students in his school and finds that 72% of the sample prefers pizza over burgers. There are 1,500 students in the school. Based on the sample proportion, how many students in the school would be expected to prefer pizza over burgers? </span>

72

100

1,080

<span>1,500 
</span>
<span>1500 / 100</span>×72<span>= 1080</span><span>

</span>
7 0
4 years ago
Michelle put $2000 in a savings account at 1.75 percent interest. she kept it there for eight years. how much interest did she e
Ivahew [28]
I = P x R x T
I = 2000 x 0.0175 x 8
I = $280
5 0
3 years ago
Read 2 more answers
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