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1 year ago

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The ABC Toy Company is creating two similar pieces for a board game, as shown below. Find the value of x that makes the two piec

es similar.
Triangle ABC is shown with sides AB marked as 6, BC marked as 7, and AC marked as y. Triangle DEF is shown with sides DE marked

1 answer:

pantera1 [17]1 year ago

7 0

Using proportions, the value of x that makes the triangle similar is of x = 14.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, we want the triangles to be similar, hence the lengths of it's sides follow the proportion given next:

$\frac{6}{12} = \frac{7}{x}$

Applying cross multiplication:

6x = 12 x 7

x = 2 x 7

x = 14.

The value of x that makes the triangle similar is of x = 14.

More can be learned about proportions at brainly.com/question/24372153

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3 years ago

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3 years ago

I need to show how to find these solutions 1/4 and 3/4 by completing the square!

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Answer:

See explanation, and ask for more details if unclear!

Step-by-step explanation:

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3 years ago

Read 2 more answers

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

<em>The distance b between each beam is 9ft.</em>

Let:

<em /> $I \to$ <em> I-Beam</em>

<em /> $d_I \to$ <em> distance between I beam and the bridge</em>

<em /> $b \to$ <em> distance between each I beam</em>

<em />

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

<em /> $Length = 55ft\ 6in$ <em> --- length of the bridge</em>

<em />

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

<em>Hence, the distance (b) between each beam is 9ft.</em>

Read more about lengths at:

brainly.com/question/22059747

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3 years ago