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slavikrds [6]
2 years ago
5

Which do you think is easier to understand and why do you think so, multiplying radicals or multiplying polynomials?

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
3 0

I believe that its easier to understand the multiplication of a radical than that of a polynomial.

<h3>How to illustrate the information?</h3>

In mathematics, a radical is the opposite of an exponent that is represented with a symbol '√' also known as root.

A polynomial is an expression which is composed of variables, constants and exponents, that are combined using the mathematical operations such as addition, subtraction, multiplication and division.

When multiplying radicals with the same index, multiply under the radical, and then multiply in front of the radical. An example is:

= 3✓2 × 4✓2

= 12✓4

= 12 × 2

= 24

The multiplication of a radical is easier.

Learn more about polynomial on:

brainly.com/question/2833285

#SPJ1

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Whitepunk [10]
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If 1 inch is 4 feet, multiply 4 times 2, and you will get 8.
4 0
3 years ago
Please help with this 2 part question and ignore the option I already clicked
melomori [17]

Answer:

B i think

Step-by-step explanation:

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7 0
3 years ago
Please help !
nadya68 [22]

Answer:

r(-2)= -5

r(0)= -7

r(5)= -12

6 0
2 years ago
Is my answer correct or no? <br> ---&gt; show explanation &amp; details if i am wrong!!!
neonofarm [45]

Answer:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer

Step-by-step explanation:

From the graph of the circle

∵ The center of the circle F is at the origin

∴ F is (0 , 0)

∵ The circle passes through point (7 , 0)

- The length of the radius of the circle is the distance between

   the center of the circle and a point on the circle

∴ r is the distance between points (0 , 0) and (7 , 0)

∴ r=\sqrt{(7-0)^{2}+(0-0)^{2}}=\sqrt{49}=7

∴ The length of the radius of the circle is 7 units

Let us find the distance between point (7 , -7) and the origin (0 , 0)

  • If the distance is equal to the radius of the circle, then the point is on the circle
  • If the distance is greater than the radius, then the point is outside the circle
  • If the distance is less than the radius, then the point is inside the circle

∵ The distance =  \sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}

∵ r = 7

∵ 7\sqrt{2} > 7

∴ The distance is greater than the radius of the circle

∴ Point (7 , -7) lies outside the circle

The correct answer is:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle

<em>Your answer is not correct, the correct answer is the 3rd answer</em>

3 0
3 years ago
Write x2 − 8x + 13 = 0 in the form (x − a)2 = b, where a and b are integers
Marrrta [24]
X^2 - 8x + 13 = 0
subtract 13 from both sides
x^2 - 8x = -13
-8/2 = -4,   (-4)^2 = 16,  add 16 to both sides
x^2 - 8x + 16 = -13 + 16
factor the left side
(x - 4)^2 = 3
3 0
3 years ago
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