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2 years ago

Can someone help me with this having trouble and show work please!!

Mathematics

1 answer:

Kaylis [27]2 years ago

6 0

Answer:

7a + b

Step-by-step explanation:

5a + 2a + 3b - 2b

= 7a + 3b - 2b

= 7a + b

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Given sec (theta) = 3 what is the exact value of csc (90 - (theta))

sp2606 [1]

Sec θ = 3
1/cos θ = 3
cos θ = 1/3

csc (90 - θ) = 1/sin (90 - θ) = 1/cos θ = 1/(1/3) = 3

Therefore, csc (90 - θ) = 3.

5 0

3 years ago

Solve this system of equations:

Natali [406]

Answer:

Step-by-step explanation:

4(2y -8) + y = 13

8y - 32 + y = 13

9y - 32 = 13

9y = 45

y = 5

x = 2(5) - 8

x = 10 - 8

x = 2

(2, 5)

3 0

3 years ago

How do you find "a" in -10+a=6a-7a please help I do not know how to find what the answer is.

Sunny_sXe [5.5K]

-10 + a = 6a - 7a

Rearrange the left hand side

a - 10 = 6a - 7a

Simplify 6a - 7a

a - 10 = -a

Add a on both sides

2a - 10 = 0

Add 10 on both sides

2a = 10

Divide by 2 on both sides

a = 5

4 0

3 years ago

64 teams participate in a softball tournament in which half the teams are eliminated after each round of play.

notka56 [123]

Answer:

After 6 rounds one team will win.

Step-by-step explanation:

This is an example of geometric progression,

Let p(n) represents the number of participants remaining after n rounds of play.

First term = 64

$\texttt{Common ratio = }\frac{1}{2}$

We have

$p(n)=a\times r^{n}\\\\p(n)=64\times \left (\frac{1}{2} \right )^{n}=2^{6}\times \left (\frac{1}{2} \right )^{n}\\\\p(n)=2^{6-n}$

Number of teams remaining after n rounds of play, p(n) = 2⁶⁻ⁿ

Here we need to find for what n p(n)=1

$2^{6-n}=1\\\\2^{6-n}=2^0\\\\6-n=0\\\\n=6$

After 6 rounds one team will win.

6 0

4 years ago

The value of a car decreases as shown in the table below. Which statements are true? Check all that apply.

Rom4ik [11]

well.. what are the statements?

8 0

3 years ago

Read 2 more answers