No daughter (0%) will have the color blindness.
<h3>How to make a cross to find the genotype of the offspring?</h3>
Genotype of woman with normal vision = XX
Genotype of man with color blindness = XYᵇ
Gametes formed from woman = X and X
Gametes formed from man = Xᵇ and Y
Crossing both the parents (Using Punnett square):
X X
Xᵇ XXᵇ XXᵇ
Y XY XY
Out of the four progeny 2 are boys and 2 are girls.
Sons do not carry the gene for color blindness.
Daughters are the carrier for the color blindness.
No daughter will have the color blindness. They are the carriers for the disorder.
Learn more about color blindness cross here:
brainly.com/question/3600715
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