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inysia [295]
2 years ago
5

Please please answer

Mathematics
1 answer:
Nostrana [21]2 years ago
3 0

Answer:

thanks for your support of the personal information on the direction of economics class

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Jessica has 900 feet of fencing and a very large
zlopas [31]

Answer:

wot

Step-by-step explanation:

this is not a full question I don't know what to tell ya bud

7 0
3 years ago
A) An angle measures 59º. What is the measure of its complement
mojhsa [17]
A) 31 degrees
b) 118 degrees
7 0
3 years ago
A system of identifying call letters uses call letters that begin either with E or W. Some have a total of 2 letters, and others
Klio2033 [76]

Answer:

If repetition is allowed then the different call letters possible are 1404.

If repetition is allowed then the different call letters possible are 1250.

Step-by-step explanation:

The call letter are of either 2 letter or 3 letters.

And for them to be identified they should start with either E or W.

  • If Repetition is allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : <u>E</u> _

The second place can be filled any of the 26 letters.

Possible number of call letters starting with W : <u>W</u> _

The second place can be filled any of the 26 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : <u>E</u> _ _

The second place and third place can be filled with any of the 26 letters.

Possible number of call letters starting with W : <u>W</u> _ _

The second place and third place can be filled with any of the 26 letters.

Total number of possible letters: 26 + 26 + (26)² + (26)² = 1404

Thus, if repetition is allowed then the different call letters possible are 1404.

  • If Repetition is not allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : <u>E</u> _

The second place can be filled any of the 25 letters.

Possible number of call letters starting with W : <u>W</u> _

The second place can be filled any of the 25 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : <u>E</u> _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Possible number of call letters starting with W : <u>W</u> _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Total number of possible letters: 25 + 25+ (25 × 24) + (26 × 24) = 1250

Thus, if repetition is allowed then the different call letters possible are 1250.

5 0
3 years ago
Multiple Choice The perimeter of a square
Oduvanchick [21]

Answer:

The answer is B, 5.

Step-by-step explanation:

3x+2 is per side. A square has 4 sides. 3x+2 times 4 is 12x+8 (using the distributive property).

12x+8 = 68

12x = 60

divide both sides by 12...

60/12 = 5.

Therefore x =5

5 0
3 years ago
I GIVEEEEEE BRAINLILSTTTTTT
astra-53 [7]

Answer:

well then try to reinvert it an then x + - an divied it see how easy

Step-by-step explanation:

5 0
3 years ago
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