Since it decreases by 36 each year, the change would be 36+36+36+36=36*4=144
For a, we can plug in values for t, so 2000-(200*1)=1800 for the first year,
2000-(200*2)=1600 - do you see the pattern here? It subtracts by 200 every year, so 1600-200=1400 for the third year and 1400-200=1200 for the fourth year.
0.2(d-b)=0.3b+5-3+0.1d
you first distribute the 0.2 to the d and b in the parentheses, you'll then get
0.2d-0.2b=0.3b+5-3+0.1d
now you make sure that the b variables are with each other on the same side of the equal sign. so you subtract 0.3b from both sides to get
0.2d-0.5b=5-3+0.1d
now do the same thing with the d variables so subtract 0.1d from both sides to get
0.1d-0.5b=5-3
now you can subtract 5-3 which is easy to get
0.1d-0.5b=2
now you have to figure out what d and b equal. so i'll do b first. all you do is use the equation you have now and pretend that d is 0 so substitute the 0 in with the d variable to get
0.1(0)-0.5b=2
now you divide -0.5b from both sides to get
-0.5b/-0.5= b 2/-0.5= -4
so now you know b = -4
now you do sthe sane thing with b substitute with a 0 to get
0.1d-0.5(0)=2
then divide 0.1d from both sides to get
0.1d/0.1=b 2/0.1=20
now you know d = 20
( d=20, b=-4 )
Answer:
Step 1: We make the assumption that 850 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$x.
Step 3: From step 1, it follows that $100\%=850$100%=850.
Step 4: In the same vein, $x\%=153$x%=153.
Step 5: This gives us a pair of simple equations:
$100\%=850(1)$100%=850(1).
$x\%=153(2)$x%=153(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{850}{153}$
100%
x%=
850
153
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{153}{850}$
x%
100%=
153
850
$\Rightarrow x=18\%$⇒x=18%
Therefore, $153$153 is $18\%$18% of $850$850.
Step-by-step explanation:
Got this off of the web ages ago i got a question like this and this is what i wrote
Answer:
$250
Step-by-step explanation:
First, you should make a graph plotting "h" as the y-axis and "t" as the x-axis. Then, you can plot the equation they give you in the question.
Part A is asking about the slope of the graph. Basically, you need to find the rise over the run each second.
Part B is asking about the "h"-intercept, or the y-intercept. When Johnny first began his ride, exactly 0 seconds passed, and he was at the top of the hill.
Part C is asking you to find how long it will take to travel a third of the way down the hill. (I think the answer should be 5 seconds, but I'll leave it to you to figure out why.)