2. (01.01 LC)

Select the correct answer.

dimulka [17.4K]

Answer:

A, y=-6

Step-by-step explanation

Because it isssssssssssssssssssssssssss a watermelon

3 0

3 years ago

A jug has a maximum capacity of 14 liters. is filled to 60% of its capacity, and then poured out at a rate of 60 mL/s. Which of

ZanzabumX [31]

Answer:

W(x) = 3.4 L - (25/1000)(L/s)*x

Step-by-step explanation:

it a tip

W(x) = 3.4 L - (25/1000)(L/s)*x

The maximum of the jug is 4 L.

now, the jug is 85% filled, then the amount of water in the jug is:

(85%/100%)*4L = 0.85*4L = 3.4L

Now, we pour 25 mL each second, so we could write a linear equation as:

W(x) = 3.4L - (25ml/s)*x

where x is the number of seconds that passed since the beginning,

But we want to write this in Liters, we have that:

1L = 1000mL.

Then 1mL = (1/1000) L

then we can write 25 mL as:

25m L = 25*(1/1000) L = (25/1000) L

Then we can write the equation as

W(x) = 3.4 L - (25/1000)(L/s)*x

which is the amount of water remaining in the jug after x seconds.

7 0

3 years ago

Can someone help me with this problem

xz_007 [3.2K]

Answer:

1.7 in.

Step-by-step explanation:

Draw an equilateral triangle with a horizontal side on the bottom. All sides are congruent, and all angles are congruent. Each side measures 2 inches. Each angle measures 60 degrees.

Now draw the altitude from the top vertex to the bottom horizontal side. The altitude is perpendicular to the horizontal side and bisects it. Now you have two right triangles inside the original equilateral triangle. The hypotenuse of each right triangle is a side of the original equilateral triangle. It measures 2 in. Since the bottom 2-inch side of the original equilateral triangle was bisected by the altitude, the short leg of each right triangle is half the length of the side of the equilateral triangle. Therefore, the short leg of each right triangle measures 1 inch. We can find the length of the long leg (the altitude of the equilateral triangle) by using the Pythagorean theorem. Let the unknown height be h.

$1^2 + h^2 = 2^2$