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aalyn [17]
2 years ago
7

Pls help will mark this brainlest

Mathematics
1 answer:
PilotLPTM [1.2K]2 years ago
7 0

The ordered pairs (0,13) and (10, 0) are joined to best draw the line of best fit for the given scatter plot. So, option 4 is correct.

<h3>How to draw the line of best fit for a scatter plot?</h3>

For the given scatter plot, to draw a line of best fit, the slope is to be calculated. The slope of the required line is calculated by

m = [n(∑xy) - (∑x)(∑y)]/[n(∑x²) - (∑x)²]

Where,

∑xy = sum of the product of x and y values

∑x = sum of x values

∑y = sum of y values

∑x² = sum of square values of x

n = total number of scatter points

And the y-intercept is calculated by

b = [∑y - m(∑x)]/n

Where m is the slope obtained above

<h3>Calculation:</h3>

The given scatter plot has the coordinate points:

(0,14), (1, 11), (2, 9), (3, 10),(4, 7), (5, 7), (6, 5), (7, 5), (8, 3), (9, 1), (10, 0)

Such that n = 11

Then the required components are calculated as follows:

∑x = 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55

∑y = 14 + 11 + 9 + 10 + 7 + 7 + 5 + 5 + 3 + 1 + 0 = 72

∑xy = (0 × 14) + (1 × 11) + (2 × 9) + (3 × 10) + (4 × 7) + (5 × 7) + (6 × 5) + (7 × 5) + (8 × 3) + (9 × 1) + (10 × 0) = 220

∑x² = 0² + 1² + 2² + 3² + 4² + 5² + 6² + 7² + 8² + 9² + 10² = 385

Then the slope is calculated as follows:

slope m =  [n(∑xy) - (∑x)(∑y)]/[n(∑x²) - (∑x)²]

On substituting,

m = [11(220) - (55)(72)]/[11(385) - (55)²]

⇒ m = -14/11 = -1.2727273 ≅ -1.3

∴ m = -1.3

Then calculating the y-intercept:

we have b = [∑y - m(∑x)]/n

On substituting,

b = [72 - -1.3(55)]/11

∴ b = 13

Then the slope-intercept form of the required line is

y = -1.3x + 13

When x = 0,

y = -1.3(0) + 13 = 13

When y = 0,

0 = -1.3x + 13

⇒ 1.3x = 13

⇒ x = 13/1.3 = 10

Therefore, the coordinates (0, 13) and (10, 0) give the best draw for the line of best fit.

Learn more about the scatterplot and the line of best fit here:

brainly.com/question/1518824

#SPJ1

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Answer:

1:00 a.m. (and 3:00 a.m., and 5:00 a.m.)

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The problem is to find the least common multiple (LCM) of the barking intervals. One way to find the LCM is to find the product of the factors of the numbers.

... 5 = 5 . . . . a prime number

... 8 = 2³

... 12 = 2²×3

The factor 2³ is a multiple of the factor 2², so we only need 2³ in our final product.

The LCM is then ...

... 2³×3×5 = 120 . . . . minutes

The dogs will all bark together every 120 minutes (2 hours).

2 hours after 11 p.m. is 1 a.m.

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Saiges spaceship traveled 588 kilometers in 60 seconds. Determine whether or not each spaceship trip below has the same speed as
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Answer:

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Part 2) 215km in 25s --> Does not have the same speed as  Saige's spaceship

Part 3) 649km in 110s --> Does not have the same speed as  Saige's spaceship

Step-by-step explanation:

<u><em>The complete question is</em></u>

Saige's spaceship traveled 588 kilometers in 60 seconds.

Determine whether or not each spaceship trip below has the same speed as Saige's spaceship.

441km in 45s

215km in 25s

649km in 110s

we know that

The speed is equal to divide the total distance traveled by the total time

In this problem we have that

The speed of Saiges spaceship is equal to

\frac{588}{60}=9.8\ \frac{km}{sec}

case 1) we have

441km in 45s

Find out the speed of the  spaceship trip

\frac{441}{45}=9.8\ \frac{km}{sec}

Compare the speed of the spaceship trip with the speed of Saiges spaceship

9.8\ \frac{km}{sec}=9.8\ \frac{km}{sec}

therefore

Has the same speed as Saige's spaceship

case 2) we have

215km in 25

s

Find out the speed of the  spaceship trip

\frac{215}{25}=8.6\ \frac{km}{sec}

Compare the speed of the spaceship trip with the speed of Saiges spaceship

8.6\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}

therefore

Does not have the same speed as  Saige's spaceship

case 3) we have

649km in 110s

Find out the speed of the  spaceship trip

\frac{649}{110}=5.9\ \frac{km}{sec}

Compare the speed of the spaceship trip with the speed of Saiges spaceship

5.9\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}

therefore

Does not have the same speed as  Saige's spaceship

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