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Daniel [21]
2 years ago
14

Find the approximate side length of a square game board with an area of 133in2.

Mathematics
1 answer:
svlad2 [7]2 years ago
8 0
11.53256 in is the answer
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A right rectangular prism is shown. The two dimensional net is also shown. Find the surface area of this prism.
Natasha_Volkova [10]

Hey!

------------------------------------------------

Surface Area Formula: 2LW * 2LH * 2WH

------------------------------------------------

2LW:

5 x 1 = 5

5 x 2 = 10

------------------------------------------------

2LH:

4 x 1 = 4

4 x 2 = 8

------------------------------------------------

2WH:

5 x 4 = 20

20 x 2 = 40

------------------------------------------------

Surface Area:

40 + 8 + 10= 58

------------------------------------------------

Answer:

D) 58 cm2

------------------------------------------------

Hope This Helped! Good Luck!

5 0
3 years ago
I need help understanding how to solve this problem .
ladessa [460]
5*2x|x|-6=24

10*|x|-6=24

10*|x|=30

Divided both sides of the equation by 10

|x|=3

X=3 X=-3
4 0
3 years ago
Help with circle measurements asap plzzzz​
antoniya [11.8K]

Answer:according to the formula of inscribed angle theorem

3x + 22 =  \frac{1}{2 }  \times 134

3x + 22 = 67

3x = 67 - 22

3x = 45

x =  \frac{45}{3}

x = 15

The answer is 15 degrees

3 0
3 years ago
PLEASE HELP IM STUCK
kkurt [141]

Answer:

y= 2x + 10

Step-by-step explanation:

The variable depends on the $2 so, the green box should be 2

4 0
2 years ago
Of the Students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of th
soldier1979 [14.2K]

Answer:

\frac{9}{20} students.

Step-by-step explanation:

We have been given that of the students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of the students are also involved in the drama club.

To find the students are both play a sport and a part of the drama club, we need to find 3/5 part of 6/8 as:

\text{Students who play a sport and a part of the drama club}=\frac{6}{8}\times \frac{3}{5}

\text{Students who play a sport and a part of the drama club}=\frac{3}{4}\times \frac{3}{5}

\text{Students who play a sport and a part of the drama club}=\frac{3\times 3}{4\times 5}

\text{Students who play a sport and a part of the drama club}=\frac{9}{20}

Therefore, \frac{9}{20} students play sport and part of the drama club.

5 0
3 years ago
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