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OLEGan [10]
3 years ago
8

in the xy-plane, the graph of the function f is a line. if f(2)=7 and f(12)=1, what is the value of f(7)?

Mathematics
1 answer:
Gnom [1K]3 years ago
8 0
Given that the function is a line

[f(7) - f(2)] / [7 - 2] = [f(12) - f(2)] / [12 - 2]

[f(7) - 7] / 5 = [1 - 7] / 10

[f(7) - 7] = 5 * [-6] / 10

[f(7) - 7] = - 3

f(7) = - 3 + 7 = 4
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Find the sum of the first 12 terms of the sequence. Show all work for full credit.
ehidna [41]
The difference between each term is -5, i.e. we know one of our terms is -5n. Now we just need to adjust it to get u1 correct. At n=1, -5n would give us -5 therefore we need to add 6 to get to 1. This gives us our equation:

\boxed{u_n=-5n+6}

Now we can work out the sum easily (we can use an equation using the above but personally I prefer the other one as it's less prone to mistakes):
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5 0
3 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

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(III) 27/(1 + 1/3) = 18

8 0
3 years ago
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