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EastWind [94]
2 years ago
5

Two jets leave an air base at the same time and travel in opposite directions. One jet travels 80 mi/h faster than the other. If

the two jets are 11392 miles apart after 8 hours, what is the rate of each jet

Mathematics
1 answer:
Pani-rosa [81]2 years ago
3 0

The rate of the slower jet is 672 miles per hour.

The rate of the slower jet is 752 miles per hour.

<h3>How to find the rate of the jets?</h3>

Two jets leave an air base at the same time and travel in opposite directions.

One jet travels 80 mi/h faster than the other.

let

x = rate of the slower jet

faster jet = 80 + x

Therefore,

rate = distance / time

The two jets are 11392 miles apart.

(80 + x)8 + 8x = 11392

640 + 8x + 8x = 11392

640 + 16x = 11392

16x = 11392 - 640

16x = 10752

divide both sides by 16

x = 10752 / 16

x = 672 miles per hour

rate of the faster jet = 80 + 672 = 752 miles per hour

learn  more on rate here: brainly.com/question/13975895

#SPJ1

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